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2 years ago

If triangle STU is similar to triangle VWX, which statement is true about the two triangles?

Mathematics

2 answers:

marshall27 [118]2 years ago

6 0

Answer:

D. segment TU is proportional to segment WX and ∠S is congruent to ∠V

Step-by-step explanation:

We are given that, triangles STU is similar to triangle VWX.

Now, when two triangles are similar, the order of the letters is important and so, the corresponding angles are congruent (equal) and the corresponding sides are proportional.

So, as ΔSTU is similar to ΔVWX.

ST is proportional to VW and TU is proportional to WX

∠S is congruent to ∠V and ∠U is congruent to ∠X.

Therefore, according to the options, we see that side TU is proportional to side WX and ∠S is congruent to ∠V.

Hence, option D is correct.

const2013 [10]2 years ago

4 0

B. Segment TU is proportional to segment WX, and angles S and V are proportional

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Help with this question!

zheka24 [161]

Since AS is a height issued from A and the perpendicular bisector of [MP] at the same time (given), so the triangle AMP is an isosceles triangle of vertex A. Then, AM=AP
MS=SP ( AS bisects MP as stated in the given )
AS is a common side between triangles ASM and ASP
Therefore, triangles ASM and ASP are congruent (SSS)

7 0

3 years ago

A tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s. If the tottoise walks the first part and

Ugo [173]

Answer:

120

240

Step-by-step explanation:

We call the length of first part x

Length of second part = y

In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.

So,

We have this equation,

x/4 + y/3 = 110

We take the LCM

(3x + 4y)/12 = 110

When we cross multiply

3x + 4y = 110x12

3x + 4y = 1320 ----- equation 1

For scenario 2

x/3 + y/4 = 100

When we take the LCM

(4x + 3y)/12 = 100

We cross multiply

4x + 3y = 100x12

4x + 3y = 1200 ------ equation 2

We now have two equations and we will solve for x and y using simultaneous linear equation.

3x + 4y = 1320 ----- 1

4x + 3y = 1200 ----- 2

We subtract equation 2 from 1 to get

- x + y = 120

We make y subject

y = x + 120 ----- 3

We put the value of y in equation 3 into equation 1

3x + 4(x + 120) = 1320

3x + 4x + 480 = 1320

7x + 480 = 1320

7x = 1320-480

7x = 840

We divide through by 7

x = 840/7

x = 120

We put value of x in equation 3

y = x + 120

y = 120 + 120

y = 240

120 and 240 are the lengths of the 2 parts of the journey.

Thanks

5 0

3 years ago

13 + k3= 11 Show work pls

zaharov [31]

13+3k=11
-Move constant to the right-hand side and change its sign
3k=11-13

Calculate the difference
3k=-2
Divide both sides by 3
K= -2/3

4 0

3 years ago

Which of the following statements is not true?

Aleks04 [339]

not true

answer is
x^5y^5z^5 = xyz^5

should be
(xyz)^5

8 0

3 years ago

Read 2 more answers

11. Describe and correct the error in evaluating the expression. -2(-7)= -14

Ulleksa [173]

Answer:

Step-by-step explanation:

The left side

does not equal to the right side

−

, which means that the given statement is false.

False

7 0

3 years ago