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amid [387]
3 years ago
6

Can the sides of a triangle have lengths 1, 3, and 10?

Mathematics
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

yes the sides of a triangle can have all those sides

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What is the equation, in point slope form, for a line that passes through the points (4,5) and (-3,-1)
mylen [45]

Answer:

<u>-6</u>

-7

Step-by-step explanation: (4,5) and (-3,-1)

  • Y2 represents -1
  • Y1 represents 5
  • X2 represents -3
  • X1 represents 4

<u>Y2 - Y1</u>

X2 - X1

<u>-1 - 5</u>

-3 - 4

<u>-6</u>

-7


Hope this helps you!!! :)

8 0
3 years ago
Read 2 more answers
Enter the ordered pair that is the solution to the system of equations graphed below please :]
DiKsa [7]
Hello!

Since (1, -2) is the point of intersection, then it is the solution to the system of equations. Let's test our answer to see if it's correct:

-2 = -4(1) + 2&#10;&#10;-2 = -4 + 2&#10;&#10;-2 = -2

But that's only for the first one, let's test for the second one:

-2 = 1 - 3&#10;&#10;-2 = -2

This is how we know that (1, -2) is the solution to the system of equations. Hope I helped! :3
5 0
3 years ago
Please help I don't understand this very well<br>*picture*​
Elenna [48]

Answer:

The inequality is 9 less than and equal to 5

The marked area on the line is numbers all below 5 which covers the less than and since it stop directly at 5 it's going to be equal to that as well

8 0
3 years ago
Read 2 more answers
Use a given information to create equation for the rational function. The function is written in factored form to help see how t
Mars2501 [29]

Recall that a rational function:

\frac{P(x)}{Q(x)},

has a vertical asymptote at x₀ if and only if:

Q(x_0)=0.

Also, the roots of the above rational function are the same as P(x).

Since the rational function has a vertical asymptote at x=-1, we get that its denominator must be:

Q(x)=x+1\text{.}

Since the rational function has a double zero at x=2 we get that its numerator must be of the form:

P(x)=k(x-2)(x-2)\text{.}

Finally, since the rational function has y-intercept at (0,2) we get that:

2=\frac{P(0)}{Q(0)}=\frac{k(0-2)(0-2)}{0+1}\text{.}

Simplifying the above equation we get:

\begin{gathered} \frac{k(-2)(-2)}{1}=2, \\ 4k=2. \end{gathered}

Dividing the above equation by 4 we get:

\begin{gathered} \frac{4k}{4}=\frac{2}{4}, \\ k=\frac{1}{2}\text{.} \end{gathered}

Therefore, the rational function that satisfies the given conditions is:

f(x)=\frac{\frac{1}{2}(x-2)(x-2)}{x+1}\text{.}

Answer:

The numerator is:

\frac{1}{2}(x-2)(x-2)

The denominator is:

(x+1)

4 0
1 year ago
Find the GCF of <img src="https://tex.z-dn.net/?f=18x%5E%7B3%7D" id="TexFormula1" title="18x^{3}" alt="18x^{3}" align="absmiddle
melamori03 [73]

18x^3 = 6x^3 *  1

30x^5 = 6x^3 * 5x^2


So GCF = 6x^3


Answer

6x^3

8 0
3 years ago
Read 2 more answers
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