The question involved the concept of combination because the order of the friends being picked are not considered. There are a total of 8 friends and 5 out of them are picked.
8C5 = 56
Therefore, there are 56 ways.
I think you can, sorry if i’m wrong
Answer:
1500p
Step-by-step explanation:
The spinner A has 4 possible values, and the spinner B has 3 possible values, so the total number of possibilities for both spinners is the product of these number of possibilities:
4 * 3 = 12
From these 12 possible pair of values, the ones that give a sum of 7 are:
(6,1), (4,3) and (2,5).
We have 3 cases where the sum is 7, so the probability of having a sum of 7 is 3/12 = 25%. Therefore, the probability of not having a sum of 7 is 75%
To find the expected value, we multiply the probability of each case by the value it would give. If the player wins, the school loses 10p (the player paid 20p and earned 30p), and if the player loses, the school wins 20p. So the expected value of 120 games is:
120 * (0.25 * (-10) + 0.75 * (20)) = 1500p
