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3 years ago

13

Why is a drum round and not square

2 answers:

Sunny_sXe [5.5K]3 years ago

8 0

I think it has something to do with how it sounds

Travka [436]3 years ago

3 0

A drum is round because it that specific shape helps keep the resonance within the instrument. The round walls help with the echoing the vibration. The corners of a square will only dim down the sound of the beat. Also, it's much better for the drum skin. The edges of a square drum would easily rip through the skin whereas a round drum would be able to distribute the force of a drumstick beating on it.

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The equation x + y = z relates the whole numbers x, y, and z. How does z compare to x? If it helps, consider an example where yo

xenn [34]

Answer:

Step-by-step explanation:

Given that the equation x + y = z relates the whole numbers x, y, and z.

This implies x,y,z all three are whole numbers

Hence we get x+y =z

x = z-y

where y is a whole number

So y can be 0,1,2.....

From this we can say x can take at most the value z in case y =0 other wise x has to be less than z

So comparison of x,y,z would give

$x\leq z$

( the equality applying only when y =0)

5 0

3 years ago

What is the product?

ZanzabumX [31]

To get the answer to this equation you first cancel out the 6! ;)

(x^2-1)(6x-1) / (x+1)

Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1

(x^2-1^2)(6x-1) / (x+1)

Then use the difference of squares!

(x+1)(x-1)(6x-1) / (x+1)

LASTLY cancel "x+1" !

so ur answer is (x-1) (6x-1)

That makes the correct answer to this problem answer choice (D) (x-1) (6x-1)

YW!!! ;)

6 0

3 years ago

Read 2 more answers

RHOMBUS The diagonals of rhombus ABCD intersect at E. Given that

schepotkina [342]

Answer:

<u>Question 11:</u>

$\angle DAC = 53^\circ$

$\angle AED = 90^\circ$

$\angle ADC = 74$

$DB = 16$

$AE = 6.03$

$AC = 12.06$

<u>Question 12:</u>

$\triangle ABD$ , $\triangle BAC$ , $\triangle CDA$ and $\triangle DAB$

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

Step-by-step explanation:

<u>Question 11</u>

Given

$\angle BAC = 53^\circ$

$DE = 8$

See attachment for Rhombus

Required

Determine the indicated sides

Solving (a): $\angle DAC$

Diagonal CA divides $\angle DAB$ into 2 equal angles

i.e

$\angle DAC = \angle BAC$

So:

$\angle DAC = 53^\circ$

Solving (b): $\angle AED$

The angles at E is 90 degrees because diagonals AC and BD meet at a perpendicular.

So:

$\angle AED = 90^\circ$

Solving (c): $\angle ADC$

First, we calculate $\angle ADE$ , considering $\triangle ADE$ :

$\angle ADE + \angle AED + \angle DAC = 180$

$\angle ADE + 90 + 53 = 180$

$\angle ADE + 143 = 180$

$\angle ADE = -143 + 180$

$\angle ADE = 37$

To calculate $\angle ADC$ , we have:

$\angle ADC = 2*\angle ADE$

$\angle ADC = 2* 37$

$\angle ADC = 74$

Solving (d): $DB$

From the rhombus

$DB = DE +EB$

Where

$DE =EB$

So:

$DB = 8 + 8$

$DB = 16$

Solving (e): $AE$

To do this we consider $\triangle ADE$

Using the tan formula

$tan(\angle ADE) = \frac{AE}{DE}$

$\angle ADE = 37$ and $DE = 8$

So:

$\tan(37) = \frac{AE}{8}$

$AE = 8 * \tan(37)$

$AE = 6.03$

Solving (f): $AC$

This is calculated as:

$AC = AE + EC$

Where

$AE = EC$

$AC = 6.03 +6.03$

$AC = 12.06$

<u>Question 12: Isosceles Triangle</u>

In the rhombus, all 4 sides are equal;

So, the isosceles triangle are:

$\triangle ABD$ , $\triangle BAC$ , $\triangle CDA$ and $\triangle DAB$

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

4 0

3 years ago

Sandra has taken 3 Test this Quarter. She has scored an 78%, 76%, and a 93%. Sandra wants to earn at least and 85% for the Quart

algol [13]

Answer:

I think at least a 86% hope this helps, hope i am right

Step-by-step explanation:

5 0

3 years ago

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The system of x+2y=5 and 3x+6y=k has infinite solutions find the value of k

barxatty [35]

15 I’m pretty sure but I don’t know

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3 years ago