Answer: y= 5/4 + 3/2
Step-by-step explanation: Your equation is y=mx +b. You have to subtract the second y from the first y, and the second x from the first x to find the slope. This equation would be 4-(-1) over 2-(-2). So your slope will be 5/4. Now to find the y-intercept you can choose either (x,y) point. For example if you are using (2,4) you would do b= 4-(5/4)(2). b=3/2.
Answer:
Verify x+y+z)=(x+y)+z for the following values of x,y,z
(i)x=3/4,y=5/6,z=-7/8(
ii)x=2/; 3,y=-5/6,z=-7/9(
iii)x=3/5,y=-6/9,z=2/10(
iv)x=; - 3/5, y = - 7/10, z = - 8/15 To Verify x+(y+z)=(x+y)+z (i)x=3/4,y=5/6,z=-7/8 LHS = 3/4 + (5/6 + (-7/8)) = (3/4) + (5/6 -7/8)= (3/4) + ((20-21)/24) = 3/4 - 1/24 =(18-1)/24 = 17/24
RHS = (3/4 + 5/6) + (-7/8)= (9 + 10)/12 - 7/8 = 19/12-7/8 = (38-21)/24 = 17/24
LHS = RHS = 17/24 (ii) * x = 2/3, y = - 5/6, z = - 7/9 LHS = 2/3 + (-5/6+ (-7/9) = 2/3 + (-5/6 - 7/9) = 2/3 + (-29/18) = 2/3 - 29/18
= 12/18 - 29/18 = -17/18
RHS = (2/3 + (-5/6))+(-7/9) = (2/3 - 5/6) - 7/9 = (-1/6) - 7/9 = -1/6 - 7/9 = -3/18 - 14/18 =
-17/18
LHS = RHS....
Hence verified..
Step-by-step explanation:
hope it helps u no notebook
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The answer is 23 I took the test
Answer:
It isn't possible.
Step-by-step explanation:
Let G be a graph with n vertices. There are n possible degrees: 0,1,...,n-1.
Observe that a graph can not contain a vertice with degree n-1 and a vertice with degree 0 because if one of the vertices has degree n-1 means that this vertice is adjacent to all others vertices, then the other vertices has at least degree 1.
Then there are n vertices and n-1 possible degrees. By the pigeon principle there are two vertices that have the same degree.
4/5 ,8/10, 16/20,
You multiply both numbers with the same number.
For ex. 4×2=8 5×2=10 so we have 8/10
