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3 years ago

Find angles EFG pleaseee

Mathematics

2 answers:

Bumek [7]3 years ago

3 0

Answer:

50 degrees.

Step-by-step explanation:

Angle FGE = $180-(7x+18)$ because angles on a straight line add up to 180 degrees.

Angle EFG = $180-38-(180-(7x+18))=6x-10$ (Angles in a triangle add up to 180)

$180-38-\left(-7x+162\right)=6x-10$

$180-38+7x-162=6x-10$

$7x-20=6x-10$

Add 20 to both sides:

$7x-20+20=6x-10+20$

$7x=6x+10$

Subtract 6x from both sides:

$7x-6x=6x+10-6x$

$x=10$

Angle $EFG=6x-10=6(10)-10=60-10=50$

levacccp [35]3 years ago

3 0

50 degrees
Explanation:

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Answer: x = 2

Step-by-step explanation:

$2^{2x}-2^x-12=0\\\\\text{Let u = }2^x\\\\u^2-u-12=0\\(u-4)(u+3)=0\\\\u-4=0\quad and\quad u+3=0\\u=4\qquad and\quad u=-3\\\\\text{Substitute u with }2^x\\2^x=4\qquad and \quad 2^x=-3\\2^x=2^2\quad and\quad \text{not possible}\\\boxed{x=2}$

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Answer: x = 0

Step-by-step explanation:

$3^{2x}+3^{x+1}-4=0\\\\3^{2x}+3^x\cdot3^1-4=0\\\\\text{Let u = }3^x\\u^2+3u-4=0\\\\(u+4)(u-1)=0\\\\u+4=0\quad and\quad u-1=0\\u=-4\qquad and\quad u=1\\\\\text{Substitute u with }3^x\\3^x=-4\qquad and\quad 3^x=1\\\text{not possible}\ and\quad 3^x=3^0\\.\qquad \qquad \qquad \qquad \boxed{x=0}$

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Answer: No Solution

Step-by-step explanation:

$4^x+6\cdot 2^x+8=0\\\\2\cdot 2^x+6\cdot 2^x+8=0\\\\\text{Let u = }2^x\\2u+6u+8=0\\8u+8=0\\8u=-8\\u=-1\\\\\text{Substitute u with }2^x\\2^x=-1\\\text{not possible}$