Ask question

Ask question

All categories

2 years ago

11

Sonya's backpack can carry a maximum mass of 12 kg. Her backpack is currently carrying 3/4 of that mass

1 answer:

Kitty [74]2 years ago

7 0

Answer:

12 notebooks

Step-by-step explanation:

3/4 = 9kg =3kg left

250g=4 per kg

3 x 4= 12

You might be interested in

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

<em>Jayden's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

6 0

3 years ago

Read 2 more answers

Can someone help me fill in the blank

Elden [556K]

Answer:

integer

Step-by-step explanation:

The greatest integer function produces the greatest integer less than or equal to x

8 0

3 years ago

Read 2 more answers

What is [4-{8x÷4x}]×8

Molodets [167]

Answer:

The answer you should be getting is : $16$

Step-by-step explanation:

$=\frac{64x}{4x}$

$=\frac{64}{4}$

$=16$

Hope this helped you!

~YEET !!!

8 0

3 years ago

12. If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that th

atroni [7]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

We have the following info given:

$Confidence= 0.95$ the confidence level desired

$ME =0.03$ represent the margin of error desired

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

The confidence level is 95% or 0.95, the significance is $\alpha=0.05$ and the critical value for this case using the normal standard distribution would be $z_{\alpha/2}=1.96$

Since we don't have prior information we can use $\hat p= 0.5$ as an unbiased estimator

Also we know that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

6 0

3 years ago

Write an equation perpendicular to x-4y= 20 that passes through the point (2, -5)

KIM [24]

4(x -2) +(y +5) = 0 . . . . . an equation

4x +y = 3 . . . . . . . . . . . . the equation in standard form
___
A graph can be seen at
https://www.desmos.com/calculator/3ct9gfxclj

5 0

3 years ago