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3 years ago

Can anyone help me with number 10??

Mathematics

1 answer:

Galina-37 [17]3 years ago

4 0

Answer:

y=−4/3x+10

Step-by-step explanation:

Find the negative reciprocal of the slope of the original line and use the slope-intercept form y=mx+b to find the line perpendicular to 3x−4y=−2.

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Show that there is no solution for the radical equation 4w+4=-4.

Ad libitum [116K]

Answer:

there is a solution

w= -2

Step-by-step explanation:

4w+4=-4

-4 -4

4w=-8

/4 /4

w=-2

3 0

3 years ago

Which angles are corresponding angles?

FromTheMoon [43]

Answer:

D, E, F, C,

Step-by-step explanation:

8 0

3 years ago

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Someone pls help . Thank you sm !!

NemiM [27]

Answer:

28 = -3k + 7

28 - 7 = -3k

21 = -3k

21/-3 = k

k = -7

1/5 x - 17 = 3

x/5 = 3 + 17

x/5 = 20

x = 5*20

x = 100

82 = 7/10 G + 12

82 - 12 = 7G/10

70 = 7G/10

70*10 = 7G

700 = 7G

700/7 = G

G = 100

6 0

3 years ago

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12=10(s+4)+50 what is the written problem to this can you help me with the answer

muminat

Answer:

s = -7.8

Step-by-step explanation:

from the question 12=10(s+4)+50

<u>first step</u>

open the bracket and evaluate for the value of s

12=10(s+4)+50

12 = 10s + 40 + 50

12 = 10s + 90

collect or combine the like terms

12-90 = 10s

-78 = 10s

divide both side by 10

-78/10 = 10s/10

-7.8 = s

therefor s = -7.8

8 0

2 years ago

A conical container can hold 120π cubic centimeters of water. The diameter of the base of the container is 12 centimeters.

Tanzania [10]

Answer: The height of the container is 10 centimeters. If its diameter and height were both doubled, the container's capacity would be 8 times its original capacity.

Step-by-step explanation:

The volume of a cone can be calculated with this formula:

$V=\frac{\pi r^2h}{3}$

Where "r" is the radius and "h" is the height.

We know that the radius is half the diameter. Then:

$r=\frac{12cm}{2}=6cm$

We know the volume and the radius of the conical container, then we can find "h":

$120\pi cm^3=\frac{\pi (6cm)^2h}{3}\\\\(3)(120\pi cm^3)=\pi (6cm)^2h\\\\h=\frac{3(120\pi cm^3)}{\pi (6cm)^2}\\\\h=10cm$

The diameter and height doubled are:

$d=12cm*2=24cm\\h=10cm*2=20cm$

Now the radius is:

$r=\frac{24cm}{2}=12cm$

And the container capacity is

$V=\frac{\pi (12cm)^2(20cm)}{3}=960\pi cm^3$

Then, to compare the capacities, we can divide this new capacity by the original:

$\frac{960\pi cm^3}{120\pi cm^3}=8$

Therefore, the container's capacity would be 8 times its original capacity.

6 0

2 years ago

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