3 years ago

I want answer for third question 3rd**

Mathematics

1 answer:

padilas [110]3 years ago

6 0

I think it is 1 I am not sure tho

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F (x + 5) - 2(4x - 1) = 0, what is the value of x?

schepotkina [342]

It is a.1

(1+5) - 2(4(1)-1) = 0

(6) - 2(3) = 0

6 - 6 = 0

0=0

4 0

3 years ago

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

I NEED HELP! PLEASE HELP!

Amanda [17]

Answer:

2400 mm

Step-by-step explanation:

(80 x 60) - (60 x 40)

7 0

3 years ago

What is the mean of this data set: 18, 15, 33, 34, 55

WARRIOR [948]

Answer:

Step-by-step explanation:

33-15=18 I belive that is the mean

8 0

3 years ago

Please help me at this math proplem thank you pleas help me

Shkiper50 [21]

which math problem?? There is many on the picture

4 0

3 years ago