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solong [7]
2 years ago
13

How do i round 186.282?

Mathematics
2 answers:
liq [111]2 years ago
8 0
Okay so if you want to know how to Round all you have to remember is 4 or more add 1 more 4 or less just ignore.

If your rounding 186.282 in the tenths you would look in your tenths place and look at the number in the left. ( the number in the tenths place is 8)

So is 2 greater or lesser than 4?

its lesser.


so ignore the rest of the two numbers there ( 8 & 2)

And your answer would be 186.2







adoni [48]2 years ago
6 0

Well, first you need to decide what place you want to round it TO.

Example:  Round it to the nearest hundredth:

The next larger hundredth is  186.29 .
The next smaller hundredth is  186.28 .
Now look at it.
186.282  is closer to  186.28  than it is to  186.29 .
So the nearest hundredth is  186.28 .

-- When  186.282  is rounded to the nearest hundredth, it becomes  186.28 .

Similarly . . .
-- When  186.282  is rounded to the nearest tenth, it becomes  186.3 .
-- When  186.282  is rounded to the nearest whole number, it becomes  186 .
-- When  186.282  is rounded to the nearest ten, it becomes  190 .
-- When  186.282  is rounded to the nearest hundred, it becomes  200 .
-- When  186.282  is rounded to the nearest thousand or anything larger,
                                                                                       it becomes  zero.

I'm curious . . . where did this number come from ?

It happens to be one thousandth of the speed of light, in miles per hour.

Did it come up in science class, or did a science geek use it for
one of the problems in math ?

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3 years ago
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Answer:

The solution of the given initial value problems in explicit form is y=x-x^2-2  and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

y'=1-2x

It can be written as

\frac{dy}{dx}=1-2x

Use variable separable method to solve this differential equation.

dy=(1-2x)dx

Integrate both the sides.

\int dy=\int (1-2x)dx

y=x-2(\frac{x^2}{2})+C                  [\because \int x^n=\frac{x^{n+1}}{n+1}]

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It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

-2=1-(1)^2+C

-2=1-1+C

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The value of C is -2. Substitute C=-2 in equation (1).

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Therefore the solution of the given initial value problems in explicit form is y=x-x^2-2 .

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