How do i round 186.282?

2 answers:

8 0

Okay so if you want to know how to Round all you have to remember is 4 or more add 1 more 4 or less just ignore.

If your rounding 186.282 in the tenths you would look in your tenths place and look at the number in the left. ( the number in the tenths place is 8)

So is 2 greater or lesser than 4?

its lesser.

so ignore the rest of the two numbers there ( 8 & 2)

And your answer would be 186.2

adoni [48]3 years ago

6 0

Well, first you need to decide what place you want to round it TO.

Example: Round it to the nearest hundredth:

The next larger hundredth is 186.29 .
The next smaller hundredth is 186.28 .
Now look at it.
186.282 is closer to 186.28 than it is to 186.29 .
So the nearest hundredth is 186.28 .

-- When 186.282 is rounded to the nearest hundredth, it becomes 186.28 .

Similarly . . .
-- When 186.282 is rounded to the nearest tenth, it becomes 186.3 .
-- When 186.282 is rounded to the nearest whole number, it becomes 186 .
-- When 186.282 is rounded to the nearest ten, it becomes 190 .
-- When 186.282 is rounded to the nearest hundred, it becomes 200 .
-- When 186.282 is rounded to the nearest thousand or anything larger,
it becomes zero.

I'm curious . . . where did this number come from ?

It happens to be one thousandth of the speed of light, in miles per hour.

Did it come up in science class, or did a science geek use it for
one of the problems in math ?

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Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad

laila [671]

Answer:

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=17$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.262$