Sqrt (y^4 * y)
Sqrt y*4 = y^2
y^2 sqrt y
Let x be the first odd number.
Second odd number will be x+2
Proof:
If 3 (was) the first odd number, 3+2 would be the next which is 5.
So,
(x) (x+2) = 99
xsquare + 2x = 99
xsquare +2x - 99 = 0
xsquare +11x - 9x -99 = 0
x(x +11) -9(x + 11) = 0
(x+11) (x-9) = 0
So the two odd numbers were 9 and 11
Answer:
I think it is 3.1
Step-by-step explanation:
make me brainlyest pls
Answer:
6+2x is the answer
Step-by-step explanation:
♡ hope it helps
