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ra1l [238]
3 years ago
8

In the paralleologram above, what is the value of x+y?

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0

Answer: F) 180°

Step-by-step explanation:

The sum of any two adjacent angles of a parallelogram is equal to 180°.

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From a pack of 9 cards numbered 1-9, three cards are drawn at random and laid on a table from left to right.
Andreas93 [3]
Answer: 1/6
Explanation: Since we need to draw three cards from a pack of 9 and the digits require an order, then our sample space becomes: 9P3.
Now, we don't care about picking an order when picking three cards to analyse, as there is only 1 way in arranging the three cards in descending order.

Thus, we get:

\frac{^{9}C_3}{^{9}P_3} = \frac{1}{6}
4 0
3 years ago
Inverse of f(x)=2x^2+5
vagabundo [1.1K]
I hope this helps you

3 0
3 years ago
Simplify without the absolute value |x+3| ; if x>2
inna [77]

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

|3|=3

|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

When is x+3 positive or zero? [greater than or equal to 0]

x+3\ge 0

Subtract 3 on both sides

x\ge -3

*|x+3|=-(x+3) if x+3 is negative or zero.

When is x+3 negative or zero? [less or equal to 0]

x+3\le 0

Subtract 3 on both sides

x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

8 0
3 years ago
If x amount of coins are tossed, find the probability that they'll all come up tails.
Pie
20 and the chance of heads would be 50/50
3 0
3 years ago
If a triangle has three angles that add up to 180 degrees angle a is 20 angle b 50 how much is angle c?
Scorpion4ik [409]
50+20=70
180-70=110°
angle c= 110°
4 0
3 years ago
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