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Viktor [21]
3 years ago
12

In the diagram, which pair of angles are vertical angles?

Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0

Answer:

angles 24 and 26 are vehicle because they are across from eachother.

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Angles of a polygon <br>thanks ♡♡♡♡​
FinnZ [79.3K]

Answer:

900 degrees

Step-by-step explanation:

The sum of the interior angles of a polygon can be found by

(n-2)*180 where n is the number of sides

This figure has 7 sides

(7-2)*180

5*180

900

7 0
3 years ago
Use the graph to answer the question. Find the slope
Liula [17]
We can take the two points given and plug them into the slope formula.

\sf~m=\dfrac{y_2-y_1}{x_2-x_1}

(-3, 3), (1, -5)
x1  y1  x2 y2

\sf~m=\dfrac{-5-3}{1-(-3)}

Subtract:

\sf~m=\dfrac{-8}{4}

Divide:

\sf~m=-2
8 0
3 years ago
Triangle DEF has sides with lengths of 6, 11, and 13 units. Determine whether this triangle is a right triangle. Show all work n
mario62 [17]

Answer:

Triangle DEF is not a right triangle ; possible lengths are 20 & 15

Step-by-step explanation:

For right triangle;

the sum of the square of the two adjacent sides must equal the square of the hypotenus.

Therefore, (6^2)+(11^2)≠(13^2).

the possible length are 20 & 15 because

(20^2)+(15^2)=(25^2)

8 0
3 years ago
The principal of a large high school wants to learn about student opinion regarding remote learning versus in person learning. E
jasenka [17]

Answer:

Step-by-step explanation:

the students that are in the survey are in it because they like the subject, rather than picking students from both types of groups, the ones that aren't doing remote learning and the ones that are doing remote learning.

6 0
3 years ago
Tan^2 70° -sec^2 70°​
kipiarov [429]

Answer:

-1

Step-by-step explanation:

We need to find the value of tan² 70° -sec² 70°​.

We know that,

\sec^2\theta-\tan^2\theta=1 ...(1)

We can write the given expression as :

tan² 70° -sec² 70° = -(-tan² 70° +sec² 70°)

=-(sec² 70°-tan² 70°)

Using identity (1)

=-(1)

= -1

Hence, the value of the given expression is -1.

4 0
3 years ago
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