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3 years ago

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There were 3 bananas, 4 apples, and 3 oranges in a basket. What is the probability that Ace will pick a banana from the basket?

1 answer:

Jlenok [28]3 years ago

5 0

0.3 or 30%. The probability that Ace pick a banana from a basket that content others fruits is 0.3.

The key to solve this problem is using the equation of probability $P(A)=\frac{n(A)}{n}$ where n(A) the numbers of favorables outcomes and n the numbers of possible outcomes.

There are in the basket 10 fruits in total (3 bananas + 4 apples + 3 oranges = 10fruits). Then, extract a fruit can occur in 10 ways, this is n. There is only 3 bananas in the basket, so the fruit that ACE will pick be a banana can occur in 3 ways out of 10, so 3 is n(A).

Solving the equation:

$P(A)=\frac{3}{10}=0.3$

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Genrish500 [490]

Given

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we have

$\sqrt{x+b}=\dfrac{d-c}{a}$

Squaring both sides, we have

$x+b=\dfrac{(d-c)^2}{a^2}$

And finally

$x=\dfrac{(d-c)^2}{a^2}-b$

Note that, when we square both sides, we have to assume that

$\dfrac{d-c}{a}>0$

because we're assuming that this fraction equals a square root, which is positive.

So, if that fraction is positive you'll actually have roots: choose

$a=1,\ b=0,\ c=2,\ d=6$

and you'll have

$\sqrt{x}+2=6 \iff \sqrt{x}=4 \iff x=16$

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

$a=1,\ b=0,\ c=10,\ d=4$

and you'll have

$\sqrt{x}+10=4 \iff \sqrt{x}=-6$

Squaring both sides (and here's the mistake!!) you'd have

$x=36$

which is not a solution for the equation, if we plug it in we have

$\sqrt{x}+10=4 \implies \sqrt{36}+10=4 \implies 6+10=4$

Which is clearly false

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3 years ago

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o-na [289]

3a^3 is the answer

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Step-by-step explanation:

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2 years ago

F(x)=- square root x-2. +3

sukhopar [10]

Answer:

Hi, The.

The domain of a function is the set of all possible values for x. The range is all possible values for y.

You should be able to see these pretty easily from the graph. If I understand your function correctly:

f(x) = square root(x+2) - 3

then x cannot be less than -2. Your domain is x > -2. In interval notation [-2,∞)

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Hope this helps!

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2 years ago