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3 years ago

What is the nth term rule of the linear sequence below?

Mathematics

1 answer:

Katena32 [7]3 years ago

6 0

Answer:

4n -13

Step-by-step explanation:

notice that the difference between the adjacent terms is 4.

nth term is given by:

nth term = first term + (n-1) × difference -n is any number

= -9 + (n-1) × 4

= -9 + 4n -4

= 4n -13

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On the number line 0.2 would be located. Choose a answer to make a true statement.

Mariulka [41]

Um, there are no choices, so I'll just tell you were it'd be located

Since 0.2 isn't yet 1, but its value is more than 0, it would be located in the middle of 1 and 0.

6 0

3 years ago

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$

Therefore, the probability is P=0.410.

4 0

3 years ago

Solve the system of equations<br>13х – 6у = 22<br><br> x=y+6

Mrrafil [7]

Answer:

x = -2, y = -8

Step-by-step explanation:

13(y + 6) - 6y = 22

=> 13y + 78 - 6y = 22

=> 7y = -56

=> y = -8

x = -8 + 6

=> x = -2

4 0

3 years ago

Someone please HELP!?

jeka94

A negative exponent just means that the base is on the wrong side of the fraction line, so you need to flip the base to the other side.

For example

$x^{-2}=\frac{1}{x^2}$

or

$( \frac{2}{5} )^{-4}=( \frac{5}{2} )^4$

***************************************
$(8r^{-5})^{-3}$

$(8* \frac{1}{r^5} )^{-3} \\\\( \frac{8}{r^5} )^{-3}
 \\ \\ ( \frac{r^5}{8} )^3
\\\\ \mathrm{Apply\:exponent\:rule}:\quad *\left(\frac{a}{b}\right)^c=\frac{a^c}{b^c} \ \ \ \ \ \ \ \ \ \ \ \ *(a^b)^c=a^{bc}
 \\\\( \frac{r^{15}}{8^3} )
\\\\( \frac{r^{15}}{512} )$

The answer is "D"

7 0

3 years ago

Homeroom Data of Tickets Sold:

cricket20 [7]

1. the mean is 16

2. the mean is 22.5

the formula that can be used to calculate the mean is

= sum of terms/number of terms

for the first question the mean can be calculated as follows

sum of terms= 20+15+19+16+10

= 80

number of terms= 5

mean= 80/5

= 16

for the second question the mean can be calculated as follows

sum of terms= 19+23+11+30+27+27+22+26+16+24

= 225

number of terms= 10

mean= 225/10

= 22.5

Hence the mean for the first expression is 16 and the mean for the second expression is 22.5

Please see the link below for more information

brainly.com/question/26159926?referrer=searchResults

8 0

3 years ago