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Andrei [34K]
3 years ago
12

Three friends go to the local framers market. Latasha spends $3.35. Helen spends 4 times as much as Latasha. Dee spends $7.50 mo

re then Helen. How much does Dee spend?
Mathematics
1 answer:
mylen [45]3 years ago
8 0

Given:

Latasha spends $3.35

Helen spends 4 times as much as Latasha.

Dee spends $7.50 more then Helen.

To find:

The amount Dee spends.

Solution:

It is given that, Latasha spends $3.35.

Helen spends 4 times as much as Latasha.

So, Helen spends = 4 × $3.35

                              = $13.40

Dee spends $7.50 more then Helen.

Dee spends = $13.40+$7.50

                    = $20.90

Therefore, dee spends $20.90.

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frosja888 [35]
The answer is C if its not tell me but if so give me 5 stars and send me a friend request.


4 0
4 years ago
What is the minimum velocity attained on the interval 0
kupik [55]

Answer:

0.630

Step-by-step explanation:

Simply evaluating, we get v (0) = 1, v (0.31831) = 0.630, v (2) = 1.566. Thus, the minimum velocity over the interval [ 0, 2] is 0.630.

3 0
3 years ago
In the figure, lines a, b, and c are parallel and m∠4=68° . Drag and drop the correct angle measure for each angle. m∠1 = m∠2 =
melisa1 [442]
The complete question in the attached figure

we have that
<span>m∠4=68°

we know that
</span>m∠4 and m∠3 are supplementary angles
so
m∠3=180-m∠4----- m∠3=180-68------> m∠3=112°

m∠3 = m∠2 --------> by alternate interior angles
so
m∠2=112°

m∠1 = m∠4 --------> by alternate exterior angles
so
m∠1=68°

m∠5 = m∠4---------> by corresponding angles
so
m∠5=68°

the answers are
m∠1=68°
m∠2=112
m∠3=112°
m∠5=68°



3 0
3 years ago
Read 2 more answers
Help me it is below
Fofino [41]
I hope this helps you

7 0
3 years ago
Read 2 more answers
Whats balance fe+30^2 &gt;fe^2O^3
blsea [12.9K]

Answer:

You are given:

4Fe+3O_2 -> 2Fe_2O_3

4:Fe:4

6:O_2:6

You actually have the same number of Fe on both sides, The same is true for O_2 so yes this equation is properly balanced.

For added benefit consider the following equation:

CH_4+O_2-> CO_2+2H_2O

ASK: Is this equation balanced? Quick answer: No

ASK: So how do we know and how do we then balance it?

DO: Count the number of each atom type you have on each side of the equation:

1:C:1

4:H:4

2:O:4

As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:

CH_4+color(red)(2)O_2-> CO_2+2H_2O

1:C:1

4:H:4

4:O:4

Everything is now balanced.

Step-by-step explanation:

5 0
3 years ago
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