When car B passes car A, they will have traveled the same distance, d.
speed = distance/time
distance = speed * time
Car A travels t time.
Since car B starts an hour later, car B travels t - 1 time.
Car A:
d = st
s = 40t
Car B:
d = st
d = 60(t - 1)
The distance are equal, so
40t = 60(t - 1)
40t = 60t - 60
-20t = -60
t = 3
Car A started at 9 am.
9 am + 3 hours = noon.
Answer: at noon.
Answer:
There are 10 hours and 45 minutes until the bus leaves.
Given:
Principal = $10
Rate of simple interest = 2.2% per month
Number of years = 6
To find:
The value of interest.
Solution:
Formula for simple interest is:
...(i)
Where, P is principal, r is rate of interest in % and t is the time period.
Here the rate of interest is defined for per month. So, the time period is also the number of months.
[ 1 year = 12 months ]
Putting P=10, r=2.2 and t=72 in (i), we get
The simple interest is $15.84.
Therefore, the correct option is B.
Answer:
im not sure but i think it is -7
Step-by-step explanation:
i think so just because looking at the top example but i might be wrong