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algol13
3 years ago
12

How do I solve this step by step?

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0
First change each term to its radical form and simplify.
2^(5/2)= sqrt(2^5)=4sqrt2
2^(3/2)= sqrt(2^3)=2sqrt2
Now subtract
4sqrt2 - 2sqrt2 = 2sqrt2
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Given the function f(x)=2x-1<br> Evaluate: <br>a) 2f(x) <br> b) f(2x)​
Dmitrij [34]

Answer:

a) 2f(x) = 4x - 2

b) f(2x) = 4x - 1

Explanation:

Given function:

  • f(x) = 2x - 1

a) 2f(x)

2f(x) = 2(2x - 1)

       = 4x - 2

b) f(2x)

f(2x) = 2(2x) - 1

       = 4x - 1

3 0
1 year ago
Anyone can help asap?
Varvara68 [4.7K]

Company A: 120 + 0.50x

Company B: 60 + 0.60x

Company A = Company B (solve for x)

(Here, x = miles)


120 + 0.50x = 60 + 0.60x

120 - 60 = 0.60x - 0.50x

60 = 0.10x

600 = x

7 0
3 years ago
Towns P,Q,R and S are shown. Q is 35 km due East of P S is 15km due West of P R is 15km due South of P Work out the bearing of R
Anni [7]

Answer:

Part A

The bearing of the point 'R' from 'S' is 225°

Part B

The bearing from R to Q is approximately 293.2°

Step-by-step explanation:

The location of the point 'Q' = 35 km due East of P

The location of the point 'S' = 15 km due West of P

The location of the 'R' = 15 km due south of 'P'

Part A

To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that \overline{RP} = \overline{SP}, the right triangle ΔRPS is an isosceles right triangle

∴ ∠PRS = ∠PSR = 45°

The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°

Part B

∠PRQ = arctan(35/15) ≈ 66.8°

Therefore the bearing  from R to Q = 270 + 90 - 66.8 ≈ 293.2°

6 0
3 years ago
I WILL MARK BRAINLIST
Taya2010 [7]

Okay so to get this answer u have too Take 17 and subtract 2 This equals 15, So the answer would be 15, This is how I get my answers at least

8 0
3 years ago
Terry spent $33.25 to have 475 fliers printed for his business. What was the cost of a single flier?​
Elanso [62]

Answer:

Step-by-step explanation:

divide 33.25/475 and you'll get 7 cents per flier

4 0
2 years ago
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