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gayaneshka [121]
3 years ago
7

An ice cream shop owner pays $0.12 per regular cone and $0.23 per waffle cone. Customers are allowed to choose which type of ice

cream cone they would prefer.If two thirds of the 276 vibes sold last week were waffle cone, how much did the owner spend on waffle cones last week?
Mathematics
2 answers:
kirill [66]3 years ago
5 0

Answer:

Last week the owner spend <u>$42.32</u> on waffle cones.

Step-by-step explanation:

Given:

An ice cream shop owner pays $0.12 per regular cone and $0.23 per waffle cone. Customers are allowed to choose which type of ice cream cone they would prefer.

If two thirds of the 276 vibes sold last week were waffle cone.

Now, to find the amount the owner spend on waffle cones last week.

Last week waffle cone sold were = \frac{2}{3}\ of\ 276.

=\frac{2}{3} \times 276\\\\=\frac{552}{3} \\\\=184.

<u><em>Last week number of waffle cones sold were = 184.</em></u>

<u><em>Price of per waffle cone = $0.23.</em></u>

Now, to get the owner spend on waffle cones last week we multiply last week number of waffle cones sold were by price of per waffle cone:

184\times 0.23\\\\=\$42.32.

Therefore, last week the owner spend $42.32 on waffle cones.

AnnZ [28]3 years ago
4 0

Answer:

The owner has to spend on waffle cones last week will be 42.32 dollars.

Step-by-step explanation:

An ice cream shop owner pays $0.12 per regular cone and $0.23 per waffle cone.

If two-thirds of the 276 vibes sold last week were waffle cone, then the number of waffle cones sold last week will be (\frac{2}{3} \times 276) = 184.

Therefore, the owner has to spend on waffle cones last week will be

= (184 × 0.23) = 42.32 dollars. (Answer)

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We have been given two matrices a and b. A has 6 rows and 7 columns, while b has 7 rows and 8 columns.

Since we know that order matters in matrix multiplication. In order for matrix multiplication to be defined number of columns in the first matrix should be equal to the number of rows of in the second matrix.

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