Please help, tysm if you do :D

Mathematics

1 answer:

castortr0y [4]2 years ago

7 0

Answer:

I think it is C I don't really know but try C

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Compute F(s), the Laplace transform of f(t) = e^(5t) (t^2 +4t +7)

MakcuM [25]

Recall that

$\mathcal L_s\{t^ne^{ct}\}=\dfrac{n!}{(s-c)^{n+1}}$

Then

$F(s)=\dfrac2{(s-5)^3}+\dfrac4{(s-5)^2}+\dfrac7{s-5}$

3 0

2 years ago

Let line A be the graph of 5x + 8y = -9. Line B is perpendicular to line A and passes through the point (10,10). If line B is th

frozen [14]

Find slope of line A:
Move into slope-intercept form y = mx+b

5x + 8y = -9
8y = -5x - 9
y = (-5/8)x - 9/8

The slope of line A is -5/8.

If Line B is perpendicular to line A, then

slope Line B = negative reciprocal of slope Line A
slope Line B = 8/5

So like B has the equation

y = (8/5)x + b

If it passes through (10,10), we know that when x = 10, y = 10. Use those values to solve for b:

y = (8/5)x + b
10 = (8/5)·10 + b
10 = (8)·2 + b
10 = 16 + b
b = -6

So line B has equation 
y = (8/5)x - 6

m = 8/5 and b = -6

so

m + b = 8/5 - 6 = 8/5 - 30/5 = -22/5

So m+b = -22/5 or -4.4 in decimal form

6 0

3 years ago

A right triangle as shown below

anastassius [24]

Answer:

sin a = 7/25

cos a = 24/25

tan a = 7/24

Step-by-step explanation:

Trig. How wonderful. I get tripped up on these types of problems some times, so I decided to try to help! To start, write out the three ratios.

SOH (sine=opposite/hypotenuse) CAH (cosine=adjacent/hypotenuse) TOA (tangent=opposite/adjacent)

Then, label the triangle with “hypotenuse” “adjacent” and “opposite.” This helps us correctly use and find the raitos. Then, use these ratios to find out the ratios of A!

sin a = 7/25

cos a = 24/25

tan a = 7/24

If needed, just divide the ratios to get their decimal form!