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Oksanka [162]
3 years ago
7

A common antacid contains the acid-neutralizing agent sodium hydrogen carbonate. Write the chemical formula for sodium hydrogen

carbonate.
Chemistry
1 answer:
kaheart [24]3 years ago
3 0
Sodium hydrogen carbonate has:
sodium \:  ion ( {Na}^{+}), hydrogen \\  ion ( {H}^{+}), and \:  carbonate \\ ion ( {CO3}^{2-})
The + from Na+ and + from H+ makes 2+, and therefore the 2- from CO3 evens the charges to neutral.

Not to be confused with Sodium Carbonate, (Na2CO3), which lack an H, Sodium Hydrogen Carbonate is sometimes shortened to just Sodium Bicarbonate. It is used in the kitchen (cooking) as "baking soda."

Formula: NaHCO3
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How many moles are there in 10 dm3 of sulfur dioxide gas
snow_tiger [21]

Taking into account the room temperature and pressure, there are 0.4167 moles in 10 dm³ of sulfur dioxide gas.

RTP refers to Room Temperature and Pressure. Pressure is 1 atm and Temperature is 298K. In this case, one mole of any gas has a volume of 24 dm³ or 24,000 cm³. This volume is called the molar volume of a gas.

In other words, the molar volume (the amount of space occupied by one mole) of any gas is 24dm³ (1 mol of gas molecules occupies 24.0 dm³).

Therefore, the amount of volume occupied by any gas can be calculated by multiplying the number of moles of gas by 24dm³:

Volume = Moles of gas× 24 dm³

So, the number of moles can be calculated as:

Moles of gas= Volume÷ 24 dm³

In this case, you know that volume if sulfur dioxide gas is 10 dm³. So, replacing:

Moles of gas= 10 dm³ ÷ 24 dm³

Solving:

Moles of gas= 0.4167

Finally, there are 0.4167 moles in 10 dm³ of sulfur dioxide gas.

Learn more about Room Temperature and Pressure:

  • <u>brainly.com/question/23119191?referrer=searchResults</u>
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C(S)+O2(g)--&gt;CO2(g)
soldi70 [24.7K]

<u>Answer:</u> The correct answer is 1.18 g.

<u>Explanation:</u>

We are given a chemical equation:

C(S)+O2(g)\rightarrow CO_2(g)

We know that at STP conditions:

22.4L of volume is occupied by 1 mole of a gas.

So, 2.21L of carbon dioxide is occupied by = \frac{1}{22.4L}\times 2.21L=0.0986mol of carbon dioxide gas.

By Stoichiometry of the above reaction:

1 mole of carbon dioxide gas is produced by 1 mole of carbon

So, 0.0986 moles of carbon dioxide is produced by = \frac{1}{1}\times 0.0986=0.0986mol of carbon.

Now, to calculate the mass of carbon, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of carbon = 0.0986 mol

Molar mass of carbon = 12 g/mol

Putting values in above equation, we get:

0.0986mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=1.18g

Hence, the correct answer is 1.18 g.

3 0
3 years ago
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