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cestrela7 [59]
2 years ago
5

How many moles are there in 10 dm3 of sulfur dioxide gas

Chemistry
1 answer:
snow_tiger [21]2 years ago
5 0

Taking into account the room temperature and pressure, there are 0.4167 moles in 10 dm³ of sulfur dioxide gas.

RTP refers to Room Temperature and Pressure. Pressure is 1 atm and Temperature is 298K. In this case, one mole of any gas has a volume of 24 dm³ or 24,000 cm³. This volume is called the molar volume of a gas.

In other words, the molar volume (the amount of space occupied by one mole) of any gas is 24dm³ (1 mol of gas molecules occupies 24.0 dm³).

Therefore, the amount of volume occupied by any gas can be calculated by multiplying the number of moles of gas by 24dm³:

Volume = Moles of gas× 24 dm³

So, the number of moles can be calculated as:

Moles of gas= Volume÷ 24 dm³

In this case, you know that volume if sulfur dioxide gas is 10 dm³. So, replacing:

Moles of gas= 10 dm³ ÷ 24 dm³

Solving:

Moles of gas= 0.4167

Finally, there are 0.4167 moles in 10 dm³ of sulfur dioxide gas.

Learn more about Room Temperature and Pressure:

  • <u>brainly.com/question/23119191?referrer=searchResults</u>
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Answer:

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Explanation:

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4 0
3 years ago
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Consider 80.0-g samples of two different compounds consisting of only carbon and oxygen. One of the compounds consists of 21.8 g
goldenfox [79]

Answer:

  • <u><em>Ratio of the  mass carbon that combines with 1.00 g of oxygen in compound 2 to the mass of carbon that combines with 1.00 g of oxygen in compound 1 = 2</em></u>

Explanation:

First, detemine the mass of oxygen in the two samples by difference:

  • mass of oxygen = mass of sample - mass of carbon

Item                     Compound 1                        Compound 2

Sample                80.0 g                                    80.0 g

Carbon                 21.8 g                                    34.3 g

Oxygen:               80.0 g - 21.8g = 58.2 g         80.0 g - 34.3 g = 45.7 g

Second, determine the ratios of the masses of carbon that combine with 1.00 g of oxygen:

  • For each sample, divide the mass of carbon by the mass of oxygen determined above:

Sample              Mass of carbon that combines with 1.00 g of oxygen            

Compound 1      21.8 g / 58.2 g =  0.375

Compound 2     34.3 g / 45.7 g = 0.751

Third, determine the ratio of the masses of carbon between the two compounds.

  • Divide the greater number by the smaller number:

  • Ratio = 0.751 / 0.375 = 2.00 which in whole numbers is 2
6 0
4 years ago
The individual dipole moments in ammonia (NH3) do not cancel each other
kozerog [31]

Answer:

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Explanation:

                    Hydrogen Bond Interactions are those interactions which are formed between a partial positive hydrogen atom bonded directly to most electronegative atoms (i.e. F, O and N) of one molecule interacts with the partial negative most electronegative atom of another molecule.

                    Hence, in ammonia the nitrogen atom being more electronegative element than Hydrogen will be having partial negative charge and making the hydrogen atom partial positive. Therefore, the attraction between these partials charges will be the main force of interaction between ammonia molecules.

                  Other than Hydrogen bonding interactions ammonia will also experience dipole-dipole attraction and London dispersion forces.

4 0
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The reaction below virtually goes to completion because cyanide ion forms very stable complexes with Ni2+ ion:[Ni(H2O)6]2+(aq) +
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Answer:

Option A and D are correct.

Unstable species react rapidly.

Stable species do not react rapidly.

Explanation:

The complete question is attached to this solution.

The more stable a reactant is, the less reactive it will be. A stable reactant has a very stable structure in which it will avoid any perturbations. And for a reaction to occur, the bonds in the reactant must break down to form the products. A stable reactant has very strong bonds that aren't easy to break down, hence, reactions involving very stable reactants do not proceed rapidly.

And the more unstable a reactant specie is, the more rapidly it reacts. This is why the reaction involving the less stable isotope of carbon; Carbon-14 is very rapid. It is the same reason as explained above that is responsible for this. The bond between unstable species are not strong and are easily breakable, thereby leading to a quick reaction.

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Answer:

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Explanation:

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