The expression can be solved by expanding the bracket and multiplying out the terms
Therefore, the expression can be simplified as;
Alternatively, using the theorem of difference of two squares, which is
Hence,
What is the average rate of change of the function f(x)=2x+4 over the interval -4 ≤ x ≤ 1? Table
1 answer:
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Answer:
Five classes
Step-by-step explanation:
1. Sort the data
You get
1.1, 1.3, 1.6, 1.7, 2, 2.6, 2.7, 2.9, 3.2, 3.2, 3.5, 3.5, 3.9, 4.6, 4.7, 4.8, 4.8, 4.9, 4.9, 5.3, 5.7, 6.4, 6.5, 7.1, 7.5, 7.6, 8.1, 8.2, 9.2, 9.4
2. Calculate the range
Range = Max - Min = 9.4 - 1.1 = 8.3
3. Calculate the class width
Divide the range by the number of classes
8.3/5 = 1.7
Round this up to 2.
4. Decide where to start the histogram
You could use classes: 1 - 3, 3 - 5, 5 - 7, 7 - 9, 9 -11
However, even numbers are easier to read.
It would be preferable to use classes: 0 - 2, 2 - 4, 4 - 6, 6 - 8, 8 - 10
5. Prepare a frequency distribution table
Note: Each class does not include its largest possible value. Thus, a value of 2 goes into Class 2 - 4, (not Class 0 - 2).
1) We are given points on the line of the graph (0,3) and (1,1).
Rise/run represents the slope of the line.
Rise/run = -2/1 = -2.
Therefore, slope of the line is -2.
<h3>Correct option is A) -2 .</h3>2) Given equation y=7.5x-5.
From the graph we can see that line crosses x-axis at 0.667.
But we don't find any such option.
But we can see line crossing y-axis is -5.
It seems that we need to find the point where line cut y-axis.
<h3>Therefore, correct option is C option.</h3><h3>C) - 5</h3>