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3 years ago

Select all that apply.

Mathematics

2 answers:

Butoxors [25]3 years ago

6 0

10/15 8/12 and 14/21

julia-pushkina [17]3 years ago

3 0

Answer:

10/15 8/12 14/21

Step-by-step explanation:

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In an orchestra there are 42 with Woodwind players to 56 brass players what is the ratio of woodwinds to brass written as a frac

Arada [10]

3/4 is the ratio of woodwinds to to brass players

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3 years ago

HELP PLZ SUPER EZ HURRY Please some1 help me. jodi built a rectangular sandbox for her daughter. The sand measures 6 feet 5 feet

nexus9112 [7]

Answer:

To fill the sandbox, she would need 15 cubic feet.

Step-by-step explanation:

To find the volume of a box, multiply all of its dimensions together.

6ft * 5ft * 1/2ft = 15ft^3

So, since she bought 20 cubic feet of sand, she should have enough with 5 cubic feet left over.

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3 years ago

PLEASE ANSWER THIS QUICKLY

Butoxors [25]

Answer:

Yes

Step-by-step explanation:

25+144=169

the frame forms perpendicular lines meaning they are 90 degrees

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3 years ago

When a fair coin is flipped, what is the chance of getting about 50% heads- specifically between 40% and 60% heads for n=10 flip

aleksklad [387]

At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide

3 0

3 years ago

The owner of a small pet supply store wants to open a second store in another city, but he only wants to do so if more than one-

Andrei [34K]

Answer:

The answer is "The null hypothesis was rejected".

Step-by-step explanation:

Following are the right-tailed test:

Calculating the null and alternative hypothesis:

$H_0 : p = 0.3333\\\\H_a : p > 0.3333\\\\n = 150\\\\x = 64\\\\\hat{p} = \frac{x}{n} = \frac{64}{150} = 0.4267\\\\P_0 = 0.3333\\\\1 - P_0 = 1 - 0.3333 = 0.6667\\\\$

$z = \frac{\hat{p} - P_0}{[\sqrt{\frac{P_0 \times (1 - P_0 )}{n}}]}$

$= \frac{0.4267 - 0.3333}{[\sqrt{\frac{(0.3333 \times 0.6667)}{150}}]}\\\\= 2.426$

Calculating the right-tailed test:

$P(z > 2.426) = 1 - P(z < 2.426) = 1 - 0.9924 = 0.0076\\\\P-value = 0.0076\\\\\alpha = 0.05\\\\P-value < \alpha$

Therefore, we reject the null hypothesis.

This example shows that more than a third of the families own pets in this town.

5 0

2 years ago