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3 years ago

Does anyone know this

Mathematics

1 answer:

Tamiku [17]3 years ago

8 0

Answer:

I belive the answer is A

Step-by-step explanation:

So any answer with 22t would make sense, so you have A and C. In C though, it is subtracting 22, but since 6195 is the total it would have to include the 22 so it is A.

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What equation represents the line that passes through the points(6,-3) and (-4,-9)?

marysya [2.9K]

M = - 3 + 9 / 6 + 4
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- 15 = 18 + 5c
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c = - 33/5
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3 years ago

A company manufactures penny number 2 nails that are 1 inch in length. The actual length is allowed to vary by up to \displaysty

Diano4ka-milaya [45]

The absolute value equation representing the length of the nail is :

$\frac{31}{32} \leqslant x \leqslant 1 \frac{1}{32}$

A nail of length 1.05 inches is unacceptable

Actual Length of nail = 1 inch

Allowable variation = 1/32 inches

The minimum allowable length :

actual length - allowable variation

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The maximum allowable length :

Actual length + allowable variation

$1 + \frac{1}{32} = 1 \frac{1}{32}$

The length of X, of the nail must be follow the equation :

Minimum ≤ X ≤ maximum

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A nail of length 1.05 inches

Maximum nail length = 1 1/32 = 1.031

1.05 > 1.031 ; hence, it is greater than the maximum allowable length and hence, Unacceptabe

Learn more : brainly.com/question/24656203

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3 years ago

Difference between mafic intermediate and felsic magmas

Inga [223]

Both are indicators of the chemical composition of silicate minerals, magmas and rocks.

Mafic is used for silicate minerals, magmas and rocks that are composed of heavier elements, like magnesium, iron, calcium and sodium. They are dark and have high specific gravities.

<span>Opposite to the this, felsic silicate minerals, magmas and rocks in their composition have less from these heavy elements. They are composed from silicon, oxygen, aluminium and potassium, are light in color and have lower specific gravities.</span>

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MaRussiya [10]

Answer:

4) 0.001

Step-by-step explanation:

The amount (a) present in h hours is ...

a(h) = (initial value)×(1/2)^(h/(half-life))

6 days is 6×24 hours, so the amount remaining is ...

a(6×24) = 50×(1/2)^(6×24/9) = 50/2^16 ≈ 0.001 . . . . milligrams

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r-ruslan [8.4K]

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