What provides the energy that drive convection in the atmosphere and

Why do some animals defend their territory after they have mated

vodka [1.7K]

Answer:

i believe it is a

Explanation:

4 0

3 years ago

Calcium carbonate interacts with omadacycline (Nuzyra). How should this interaction be avoided?(Interactions) hint look up omada

stellarik [79]

Answer: An interaction is caused between the two medications (Calcium carbonate and Omadacycline) and causes serious negative side effects, due to the fact that when the two are taken together the body is unable to process the antibiotic therefore causing a reduction in the concentration of antiobiotics in the blood stream. this causes a reduction the body's ability to fight off the infection. In addition, drug interactions with calcium increase the risk of dangerously high calcium levels in the blood and disrupt the body´s basal state.

Explanation:

Omadacycline is a broad spectrum antibiotic. It belongs to the tetracycline group and specifically to the aminomethylcycline subclass and is used mainly in the treatment of treatment of community-acquired bacterial pneumonia and acute skin and skin structure infections. the mecanism of action of Omadacycline works like every other tetracycline antiobiotic. It inhibits the bacterial protein synthesis thereby rendurig the bacteria useless and thus stopping the replicaton of these bacterias.

Calcium carbonate on the other hand, is usuallly administered as a dietary supplement when the corporal levels of calcium do not reach sufficient levels. It may also be used as an antacid to relieve heartburn, acid indigestion, and nausea. It is available with or without a prescription and is available in many forms for example; as a tablet, chewable tablet, capsule or as a liquid.

Calcium is vital for healthy bones, muscles, nervous system, and heart. Calcium is involved in cardiac muscle contraction and electrical impulse conduction.

When calcium carbonate is taken with Omadacycline causes a significant increase in the levels of calcium in the blood. Excess levels of calcium interfere with the absorption of the antibiotic because calcium binds to the tetracycline in the intestine causing a reduction in the efectiveness. Failure to control the infection could lead to severe side effects whether temporary or permanent and in extreme cases death.

<h3>Calcium carbonate SHOULD NOT BE TAKEN WITH </h3>

Bisphosphonates
Fluoroquinolone antibiotics
H2 blockers
Proton pump inhibitors (PPIs)
Tetracycline antiobiotics (Omadacycline- Nuzyra)
Thiazide diuretics

In conclusion, calcium carbonate should not be taken with tetracycline antiobiotics in this case Omadacycline because it causes an ncrease in calcium levels which binds to the antibiotic therefore reducing its absorption by the intestine and reducing its effect in fighting off the infection. The antiobiotic should be taken two hours before the calcium carbonate or about four to six hours after.

3 0

3 years ago

Consider the following reaction:

zzz [600]

Answer:

Question 1: Both the rate of reaction of H₂O₂ and the rate of formation of H₂O are:

$6.6\cdot 10^{-3}mol/(liter.s)$

Question 2: 0.60 moles of O₂ are formed in the first 50 s of reaction.

Explanation:

The coefficients of the balanced chemical equation tells the relation of formation of the reactants into the products, which is also the relation between their rates of reaction.

The balanced chemical equation (given) is:

$2H_2O_2(aq)\rightarrow 2H_2O(l)+O_2(g)$

Then, in the same time that 2 moles of H₂O₂ react, 2 moles of H₂O and 1 mol of O₂ are formed.

1. Question 1.

That means that the rate of formation of O₂ is half the rate of reaction of H₂O₂ and half the rate of formation of H₂O.

Hence, if the instantaneous rate of formation of O₂ is 3.3×10⁻³moles/(liters×seconds), then the rate of reaction of H₂O₂ and the rate of formation of H₂O is twice:

$2\times 3.3\cdot 10^{-3}mol/(liter.s)=6.6\cdot 10^{-3}mol/(liter.s)$

2. Question 2.

First you must find how much the concentration has changed.

You can read the initial concentration of H₂O₂ on the graph. It is the y-intercept. It is 1.0M.

You can read the approixmate concentration of H₂O₂ at the time 50 s. It is about 0.2M.

Then the change in concentration in the first 50 s of reaction is about 1.0M - 0.2M = 0.8M.

Now you can convert the concentration 0.8M into number of moles, using the volume (1.5 liters), assuming the liquid volume does not change, and the molarity definition (molarity is the number of moles of solute in one liter of solution)

$\Delta [H_2O_2]=\Delta moles/Volume(liters)$

$0.8M=\Delta moles/1.5liter\\\\\Delta moles=0.8M\times 1.5liter=1.2mol$

Hence, 1.2 mol of H₂O₂ have reacted in the first 50s of reaction.

From the coefficients of the chemical equation, the number of moles of O₂ formed is half the number of moles of H₂O₂ that react.

Thus, 1.2mol/2 = 0.60 moles of O₂ are formed in the first 50 s of reaction.

7 0

3 years ago

Which type of cell is a rose thorn? prokaryotic eukaryotic plant eukaryotic animal chloroplastic

Ede4ka [16]

Plant cells are eukaryotic cells. Prokaryotic cells do not contain a membrane bound nucleus, mitochondria or other membrane bound cell structures (organelles), the DNA of prokaryotic cells are located in the cytoplasm of the cell. ... Plant cells are eukaryotic because they have a nuclear membrane.
so therefore, A rose thorn is a eukaryotic plant cell.

5 0

4 years ago

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Consider the combustion reaction of acetylene (C2H2) : 2C2H2 + 5O2 mc001-1.jpg 4CO2 + 2H2O Use the periodic table to determine h

marysya [2.9K]

1) Balanced chemical equation:

    2C2H2 + 5O2 ----> 4CO2 + 2H2O

2) State the molar ratios

   2 mole C2H2 : 5 mole O2 : 4 mol CO2 : 2 mole H2O

3) Use the periodic table to get the atomic masses of each element and from that the molar masses of O2 and C2H2

Atomic masses:

O: 16 g / mol

C: 12 g / mol

H: 1 g / mol

Molar masses of O2 and C2H2:

O2: 2 * 16 g/mol = 32 g/mol

C2H2: 2*12 g/mol + 2*1g/mol = 26 g / mol

3) Convert 859.0 grams of C2H2 into moles:

   859.9 g / 26.0 g /mol = 33.07 mol C2H2

4) State the molar proportion with C2H2 and O2

x mol O2 / 33.07 mol C2H2 = 5 mol O2 / 2 mol C2H2

=> x = 33.07 mol C2H2 * 5 mol O2 / 2 mol C2H2 = 82.68 mol O2

5) Convert 82.68 mol O2 to grams

82.68 mol * 16 g/mol = 1322.9 g O2.

Answer: 1322.9 grams of O2

7 0

3 years ago

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