Ask question

Ask question

All categories

2 years ago

7

The English Alphabet has 20 letters more than one-fourth the number of letters in the Greek Alphabet. The English Alphabet has 2

6 letters. Which of the following equations would you use to find the number of letters, g, in the Greek Alphabet?

1 answer:

melomori [17]2 years ago

7 0

20+1/4g=26 is your answer

You might be interested in

Evaluate 5x2−9 when x=−2

Elena-2011 [213]

answer: 11

explanation: just plug in -2 for x. the new problem becomes 5(-2)^2 - 9. Negative two squared is 4. 5 times 4 is 20. 20 minus 9 is 11.

3 0

2 years ago

Describe the correct the error in finding the area of the triangle

lions [1.4K]

Answer:

Since the area of a triangle is 1/2 base times height, it should be a=1/2(10)(12m)

So the area would be 60 meters squared.

Step-by-step explanation:

4 0

3 years ago

N his history class, Han's homework scores are: 100% 100% 100% 100% 95% 100% 90% 100% 0% What is the mode of Han's scores?

Basile [38]

Answer:

There is no mode

Step-by-step explanation:

3 0

3 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

The booster club for a high school football team sold adult and student tickets to a banquet.

USPshnik [31]

Answer:

<em>Hi There the correct answer to this is A 14</em>

Step-by-step explanation:

All you really need to do is Add 9 to 5 then you get your answer from 14.

4 0

3 years ago