The radius of the circle of the circle equation (x + 3/8)^2 + y^2 = 1 is 1 unit
<h3>How to determine the radius of the circle?</h3>
The circle equation of the graph is given as:
(x + 3/8)^2 + y^2 = 1
The general equation of a circle is represented using the following formula
(x - a)^2 + (y - b)^2 = r^2
Where the center of the circle is represented by the vertex (a, b) and the radius of the circle is represented by r
By comparing the equations (x - a)^2 + (y - b)^2 = r^2 and (x + 3/8)^2 + y^2 = 1, we have the following comparison
(x - a)^2 = (x + 3/8)^2
(y - b)^2 = y^2
1 = r^2
Rewrite the last equation as follows:
r^2= 1
Take the square root of both sides of the equation
√r^2 = √1
Evaluate the square root of 1
√r^2 = 1
Evaluate the square root of r^2
r = 1
Hence, the radius of the circle of the circle equation (x + 3/8)^2 + y^2 = 1 is 1 unit
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Answer:
I believe the answer is x=1.
Step-by-step explanation:
I am a bit confused on what is wanted, but g(x) is the x value on the line g. so when g(x)=1, I think x=1 on the line g.
Answer:
2x(3+1)
Step-by-step explanation:
