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aleksandr82 [10.1K]

3 years ago

11

Determine the surface area of a rectangular prism with length 1.5 feet, width 7 feet, and height 6.2 feet. 16.7 square feet 63.2

square feet 65.1 square feet 126.4 square feet

1 answer:

aleksklad [387]3 years ago

6 0

126.4 I guess.... How you wrote it is a tad confusing. Is the second set of numbers another question?

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Guys i need your HELP ASAP

ivanzaharov [21]

To solve this, you’ll first need to solve for their slopes.

The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3

We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3

The equation you get it y = 1/3x + b.

Now you will need to solve for b by substituting in the first ordered pair of line R.

2 = 1/3(1) + b.

Once you solve for b, you should get 5/3 and y = 1/3x + 5/3

Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.

y = 1/3(10) + 5/3.

Your solution should be 5.

So your answer is: a = 5

8 0

3 years ago

HELP image is provided

Hitman42 [59]

Answer:

yes

Step-by-step explanation:

angles z and b both have 2 congruent lines

angle y and a have one congruent line

and lines CA and XY have a congruent tick mark

5 0

2 years ago

Nichol walks at a constant pace of 1.2 m/s and takes 15 minutes to get to school.

liraira [26]

Answer:

The difference between the distances they walked is 600 meters.

Step-by-step explanation:

Let's calculate the distance traveled by Nichol and Sakura with the following equation:

$d = v*t$

Where:

v: is the speed

t: is the time

The distance traveled by Nichol is:

$d_{n} = 1.2 m/s*15min*\frac{60 s}{1 min} = 1080 m$

And the distance traveled by Sakura is:

$d_{s} = 1.4 m/s*20 min*\frac{60 s}{1 min} = 1680 m$

Hence, the difference between the distances they walked is:

$d_{t} = d_{s} - d_{n} = 1680 m - 1080 m = 600 m$

Sakura traveled 600 meters more than Nichol.

Therefore, the difference between the distances they walked is 600 meters.

I hope it helps you!

4 0

2 years ago

Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.

melamori03 [73]

Answer:

a) 0.8413

b) 421

c) $P_{95} = 189.675$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(IQ scores at most 180)

P(x < 180)

$P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)$

Calculation the value from standard normal z table, we have,

$P(x < 180) = 0.8413 = 84.13\%$

b) Number of the members of the club have IQ scores at most 180

n = 500

$\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421$

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

$P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95$

Calculation the value from standard normal z table, we have,

$P(z < 1.645) = 0.95$

$\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675$

$P_{95} = 189.675$

8 0

3 years ago

What is the answer to 32 3/4 - 12 1/2 =

Natasha_Volkova [10]

Answer:

20.25 :)

Step-by-step explanation:

8 0

2 years ago