Answer:
159 m
Step-by-step explanation:
From the information given:
It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.
Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.
Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.
We are to find, the magnitude of the ostrich's eastward component.
i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.
Using the Pythagoras rule:
ES² = OE² + OS²
226² = OE² + 161²
226² - 161² = OE²
OE² = 226² - 161²
OE² = 51076 - 25921
OE² = 51076 - 25921
OE² = 25155
OE = 158.60 m
OE ≅ 159 m
Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.
Answer:
V=75pi ft^3 or 235.619 ft^3
Step-by-step explanation:
area of base times length
area of circle = pi * r^2 where r = 1/2 * diameter
A = pi * 2.5^2
A= 6.25pi ft^2
multiply by length
V= 6.25pi*12
V=75 pi
Answer:
0.56 milligrams
Step-by-step explanation:
Put 6 where t is and do the arithmetic.
M(6) = 50·e^(-0.75·6) = 50·e^-4.5 ≈ 0.56 . . . . milligrams
Answer:
x³ sin(x)
Step-by-step explanation:
Tabular method is a special form of integration by parts. It works by taking derivatives of u and integrals of dv. You multiply diagonally, then sum the results, alternating the signs.
The important thing to note is that this will produce an antiderivative only if the derivatives of u eventually become 0. So the correct choice is x³ sin(x), because the derivatives of x³ eventually becomes 0:
d/dx (x³) = 3x²
d/dx (3x²) = 6x
d/dx (6x) = 6
d/dx (6) = 0
Answer:
y = -4x - 6
Step-by-step explanation:
The equation of a line in point-slope form.
is the equation of the line containing point (x1, y1) and having slope, m.
The given point of the perpendicular bisector is (-1, -2), so in this case, x1 = -1, and y1 = -2.
We need the slope of the perpendicular bisector. First we find the slope of the segment. We start at point (-5, -3). We go up 1 unit and 4 units to the right, and we are at another point on the segment. Since slope = rise/run, the slope of the segment is 1/4. The slopes of perpendicular lines are negative reciprocals, so the slope of the perpendicular bisector is the negative reciprocal of 1/4, so for the perpendicular bisector, m = -4.
Now we use the equation above and our values.
