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3 years ago

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Last night, Roberto spent 90 minutes doing homework, infinity symbol hour reading, and 540 seconds making his lunch for the next

day. How many more minutes did Roberto spend doing homework than he did reading and making his lunch?
A) 81 minutes
B) 50 minutes
C) 49 minutes
D) 41 minutes

2 answers:

Crazy boy [7]3 years ago

7 0

41 mins hope this helps

Margarita [4]3 years ago

6 0

Answer:

41 minutes

Step-by-step explanation:

We are given;

Time spent on homework = 90 minutes

Time spent reading = 2/3 hours = 2/3 × 60 minutes = 40 minutes

Time spent making lunch = 540 seconds = 540/60 minutes = 9 minutes

We want to find how many more minutes Roberto spent doing homework than he did reading and making his lunch.

Thus;

Time spent on reading and making lunch = 40 + 9 = 49 minutes

Hence, the word "how many more" means we will subtract 49 from 90.

So, "how many more minutes" = 90 - 49 = 41 minutes

Step-by-step explanation:

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Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

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The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

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Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

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2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

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x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

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$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

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7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

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Hence, function l is not defined for all real values.

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The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

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- Kolmogorov-Smirnov Test

- Q-Q Plots (the graphical method) also known as Quantile Plot

- Do not use a histogram; it is not advisable

(C) Checking for Model Misspecification, the appropriate techniques to use are:

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