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Volgvan
3 years ago
10

What is the value of b2 - 4ac for the following equation? 2x 2 - 2x - 1 = 0

Mathematics
2 answers:
yanalaym [24]3 years ago
8 0

Answer:

The value of the discriminant is 12.

Step-by-step explanation:

We are given the quadratic equation is 2x^2-2x-1=0.

Now, we know,

<em>The discriminant for the quadratic equation ax^2+bx+c=0 is given by D=b^2-4ac.</em>

On comparing the equations, we have,

a= 2, b= -2 and c= -1

So, the discriminant is given by,

D=(-2)^2-4\times 2\times (-1)

i.e. D=4+8

i.e. D= 12

Hence, the value of the discriminant is 12.

NikAS [45]3 years ago
5 0
2x^2-2x-1=0
\Delta=b^2-4ac

\Delta=(-2)^2-4*2*(-1)=4+8=12
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The sea ice area around the North Pole fluctuates between about 6 million square kilometers in September to 14 million square ki
Aleksandr [31]

Answer:

there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

Step-by-step explanation:

Given the data in the question;

Let S(t) represent the amount sea ice around the North Pole in millions of square meters at a given time t,

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Now, we use a cosine curve to model this scenario

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Hence;

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Now we find when there will be less than 9 million square meters of sea ice;

S(t) = 9

so we have

9 = 4cos( π/6 × (t-2) ) + 10

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so we have;

cos⁻¹( -1/4 ) = π/6 × (t₁-2)  -------- let this be equation 2

2π - cos⁻¹( -1/4 ) = π/6 × (t₂-2)  -------- let this be equation 3

so we solve equation 2 and 3

we have'

t₁ - t₂ = 6/π × ( 2π - cos⁻¹( -1/4 ) - cos⁻¹( -1/4 ) )

t₁ - t₂ = 6/π × ( 2π - 2cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - 104.4775 )

t₁ - t₂ = 6/π × ( π - 104.4775 )  

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