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dybincka [34]
3 years ago
7

Which is bigger 20% of 300 or 1/4 of 200

Mathematics
2 answers:
worty [1.4K]3 years ago
7 0
To find 20% of 300, multiply .2 x 300 = 60
60 is 20% of 300

1/4 = 25%
to find 25% of 200, multiply .25 x 200 = 50
50 is 1/4 of 200

20% of 300 is more than 1/4 of 200
zavuch27 [327]3 years ago
4 0
(20/100) *300 = (2/1)*30= 60 (1/4) * 200= 200/4 = 50
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If a and b are odd integers,then a-b is an even integer identify the conclusion
garri49 [273]
Any two odd integers will always add up to an even number. Examples include 1+1=2, 15+19=34, etc. 
6 0
3 years ago
F(x)3x+5/x what is f(a+2)
Natalija [7]
F(X) = (3x + 5)/X
F(a + 2) = (3(a + 2) + 5)/(a + 2)
F(a + 2) = (3a + 6 + 5)/(a+2)
F(a + 2) = (3a + 11)/(a + 2).

This would be the final solution.
4 0
3 years ago
Read 2 more answers
Y=3xy-1, Solve for y
Ket [755]

Answer:

y = \frac{1}{3x-1}

Step-by-step explanation:

Given

y = 3xy - 1

Collect terms in y on the left side by subtracting 3xy from both sides

y - 3xy = - 1 ← factor out y on the left side

y(1 - 3x) = - 1 ( divide both sides by 1 - 3x

y = \frac{-1}{1-3x} ← multiply numerator/denominator by - 1

y = \frac{1}{3x-1}

3 0
3 years ago
You and your friend are having a race, but since you are faster than him, you decide to give him a head start. He starts 10m in
Diano4ka-milaya [45]

Answer:

20 seconds

Step-by-step explanation:

Your friend starts 10 meters in front of the starting line.

You start from the starting line.

You run at 6 meters/ second.

Your friend runs at 5.5 meters/second.

You and your friend will be at the same distance from the starting line only when you are able to catch your friend.

The relative speed between you two is the difference in your speed and your friend's speed that is:

6-5.5=0.5m/s

So to cover 10 meters of separation at the speed of 0.5 meter/second it will take:

t=\frac{10}{0.5}= \frac{100}{5}=20s

So it will take 20 seconds for you and your friend to be at the same distance from the starting line.  

8 0
3 years ago
Read 2 more answers
Please help thank you very much.
spin [16.1K]
The first one is true




if the angles of a right triangle are 90,45,45

the legs are equal. so if AC is 13, Back will be 13, too.


now you can get help from Pythagoras theorem :
c  {}^{2} =  {13}^{2}  +  {13}^{2}  \\ c {}^{2}  = 169 + 169 = 338 \\ c =  \sqrt{338}  = 13 \sqrt{2}  = 18.38




good luck
4 0
3 years ago
Read 2 more answers
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