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daser333 [38]
3 years ago
10

PLZ HURRY!!!!!!!!!!!!! Simplify. −4x^2(5x^4−3x^2+x−2)

Mathematics
1 answer:
Simora [160]3 years ago
5 0

\bold{Answer}

\boxed{\bold{-20x^6+12x^4-4x^3+8x^2}}

\bold{Explanation}

  • \bold{Simplify: \ -4x^2\left(5x^4-3x^2+x-2\right)}

\bold{------------------}

  • \bold{Distribute \ Parenthesis}

\bold{\left(-4x^2\right)\cdot \:5x^4+\left(-4x^2\right)\left(-3x^2\right)+\left(-4x^2\right)x+\left(-4x^2\right)\left(-2\right)}

  • \bold{Apply \ Addition \ / \ Subtraction \ Rules: \ +\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab}

\bold{-4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2}

  • \bold{Simplify \ -4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2: \ -20x^6+12x^4-4x^3+8x^2}

\bold{-20x^6+12x^4-4x^3+8x^2}

\boxed{\bold{Eclipsed}}

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Answer:

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Step-by-step explanation:

I am solving this using Function Notation.

We are given:

q(x)= \frac{1}{2}x - 3

While we are to find:

q(x) =-4

In Function Notation, replace all the "x" you see with the value you are given.

So, in this case,

q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}x - 3

Would become

q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}(-4) - 3

Now we can solve.

\frac{1}{2}(-4) - 3

Use PEMDAS; Parenthesis first;

\frac{1}{2}(-\frac{4}{1})

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Hence, we are left with

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Therefore, the value of x is -5

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MAXImum [283]

Answer:

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Step-by-step explanation:

1) we know that

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mr_godi [17]

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