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Paladinen [302]
3 years ago
7

What are two composite numbers that each have 8 as a factor

Mathematics
2 answers:
Julli [10]3 years ago
6 0
Any number that is a multiple of 8 is one 16,24,32,40,48,56,64,72,88,96
Viktor [21]3 years ago
3 0
56 and 64 are composite and both have 8 as a factor.
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Classify each polynomial by its degree and bt its number of terms (i.e. cubic or degree=3; trinomial. (a) 5x^4-8 (b) 4a^2-2a-16
lord [1]

Answer:

a. 4th degree binomial

b. 2nd degree trinomial

c. 3rd degree monomial.

Step-by-step explanation:

In order to find each of these, start by writing the degree based on the highest exponent. The work for a is done for you below.

5x^4 - 8

This means it is a 4th degree.

Now we can decide what the final word is based on how many terms there are. In this one there is 2, so we call it a binomial.

4th degree binomial.

3 0
3 years ago
What is tan(θ/2), when tan(θ) = 4/3 and when π < θ < 3π/2?
Tamiku [17]
Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
 then,  Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.

tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]

Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9)        (sec²Ф will have a negative value, because Ф is in the        sec Ф=-5/3                                 third quadrant).

cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5

Therefore:

tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2

Answer: tan (Ф/2)=-2; when tan (Ф)=4/3


3 0
3 years ago
If you place a 5-foot ladder against the top of a 4-foot building, how many feet will the
Maksim231197 [3]

What are your options for the questions.

5 0
3 years ago
Read 2 more answers
Whats the answer 5h-8=2h+19 equality
djyliett [7]

Answer:


Step-by-step explanation:

5h-8=2h+19

5h-2h=19+8

3h=27

h=27/3

h=9

4 0
3 years ago
What percentage of babies born in the United States are classified as having a low birthweight (&lt;2500g)? explain how you got
lawyer [7]

Answer:

2.28% of babies born in the United States having a low birth weight.

Step-by-step explanation:

<u>The complete question is</u>: In the United States, birth weights of newborn babies are approximately normally distributed with a mean of μ = 3,500 g and a standard deviation of σ = 500 g. What percent of babies born in the United States are classified as having a low birth weight (< 2,500 g)? Explain how you got your answer.

We are given that in the United States, birth weights of newborn babies are approximately normally distributed with a mean of μ = 3,500 g and a standard deviation of σ = 500 g.

Let X = <u><em>birth weights of newborn babies</em></u>

The z-score probability distribution for the normal distribution is given by;

                          Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 3,500 g

            \sigma = standard deviation = 500 g

So, X ~ N(\mu=3500, \sigma^{2} = 500)

Now, the percent of babies born in the United States having a low birth weight is given by = P(X < 2500 mg)

         

   P(X < 2500 mg) = P( \frac{X-\mu}{\sigma} < \frac{2500-3500}{500} ) = P(Z < -2) = 1 - P(Z \leq 2)

                                                                 = 1 - 0.97725 = 0.02275 or 2.28%

The above probability is calculated by looking at the value of x = 2 in the z table which has an area of 0.97725.

4 0
3 years ago
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