Solve for x:(x-1)^3/2 = 27

2 answers:

8 0

(x-1)^3 / 2 = 27

For equations like this, we want to isolate x in order to get the value of it.

First, let's multiply both sides by 2 to eliminate the fraction.

(x-1)^3 = 27(2)

Now, let's take the cube root of both sides

(x-1) = ∛(27 * 2)

Now, simplify the root

x - 1 = 3∛2

Add both sides by 1

x = 1 + 3∛2

That's your answer.

Have an awesome day! :)

Angelina_Jolie [31]3 years ago

4 0

If you want the decimallll, x = 4.779763147, you probably don't need that. But whatever. XD

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First come first served <br> brainiest:) do it right

Arte-miy333 [17]

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3 0

2 years ago

X +2 times -2+107 = 180

Kryger [21]

Answer:

X = -3/7

Step-by-step explanation:

7 0

2 years ago

Billy is monitoring the exponential decay of a radioactive compound. He has a sample of the compound in a test tube in his lab.

Over [174]

Solution:

Formula for radioactive Decay is given by

$R_{0}= R(1-\frac{S}{100})^t$

$R_{0}$ = Initial Population

R = Remaining population after time in hours

Rate of Decay = S % per hour

Initial Population = 72 grams

Final population = 15 grams

Rate of Decay = 35 % per hour

Substituting the values to get value of t in hours

$72=15(1-\frac{35}{100})^t\\\\ 4.8= (0.65)^t\\\\ t= -3.64$ →→1 St expression

But taking positive value of t , that is after 3.64 hours the sample of 72 grams decays to 15 grams at the rate of 35 % per hour.

Now , it is also given that, Once the sample reaches a mass of 15 grams, Billy will continually add more of the compound to keep the sample size at a minimum of 15 grams.

Substituting these in Decay Formula

Final Sample = 15 gm

Starting Sample = 15 +k, where k is amount of sample added each time to keep the final sample to 15 grams.

Time is over 3.64 hours i.e new time = 3.64 + t

Rate will remain same i.e 35 % per hour.

$15=(15+k)(1-\frac{35}{100})^{3.64+t}$ →→→ Final expression (Second) , that is inequalities can be used to determine the possible mass of the radioactive sample over time.