The result is a line perpendicular to y=3x-2
This line has the following equation: y =mx + b, where m = slope
Remember that the product of the slopes of two perpendicular lines is always = -1 (or in other term one is the reciprocal inverse of the other) so the
first slope = 3 and the sope perpendicular to 3 will be - 1/3.
Then the new equation is y = - 1/3(x) + b
How to calculate b? This line passes through (6, 8), that
means (x=6 and y=8) . Plug these values in y = -1/3 (x)+b:3
8=(-1/3)(6) + b;
8= - 2 + b and b = 10
Te final equation is y = - 1/3.x+10 (answer A)
Answer: Option B.
Step-by-step explanation:
Given the polynomial:

Observe that
and
are perfect squares. Then, you can rewrite the polynomial in this form:

You can identify that:

Then, we can check if 

Since
, the polynomial
<em>IS NOT </em>a perfect square trinomial of the form 
F(x)= -4.
Just plug in -1 for your x in 2x-2 and solve like a normal equation. Think of f(x) a your y because that's basically what it is. If it helps, the equation is basically:
y=2x-2 so you would just solve for y by plugging in -1 into x.
She made an error in the STEP 1
she shouldnt multiply the numbers
Answer:
(y-(-2))/(x-(-1)= (-2-4)/(-1-3)
(y+2)/(x+1)= (-6)/(-4)
(y+2)/(x+1)= (3/2)
Cross multiplying
2y+4= 3x+3
3x-2y-1=0