282% = 2.82 = 282/100 reduces to 141/50
Y=40 I believe this is the answer
Answer:
Sam will get £30 while Bethan will get £24.
Step-by-step explanation:
The total ratio shared by Sam and Bethan is 5+4 = 9
1 share ratio is the total amount involved divided by the total ratio
That is, £54/9 = £6
if 1 share ratio is £6,
Sam with 5 share ratio will get £6*5 = £30
while Bethan with ratio 4 wiill get £6*4 = £24
Step 1 : Setting up the problem
Write the coefficients of the dividend in the same order. For missing terms, enter the co-efficient as zero. Set the divisor equal to zero and use that number in the division box.
The problem now looks as follows:
-1 | 12 5 3 0 -5
Step 2 : Bring down the first co-efficient and write it in the bottom row.
-1 | 12 5 3 0 -5
______________________ 12
Step 3 : Multiply the first coefficient with the divisor and enter the value below
the next co-efficient. Add the two and write the value in the bottom row.
-1 | 12 5 3 0 -5
_____-12_______________ 12 -7
Step 4 : Repeat Step 3 for rest of the coefficients as well:
-1 | 12 5 3 0 -5
____________7 ___________ 12 -7 10
-1 | 12 5 3 0 -5 ______________ -10______ 12 -7 10 -10
-1 | 12 5 3 0 -5 ____________________ 10_ 12 -7 10 -10 5
The last row now represents the quotient coefficients and the remainder. Co-efficients of Quotient are written one power less than their original power and the remainder is written as a fraction.
Answer :12x^3-7x^2+10x-10+5/(x+1) where the last term denotes the remainder and the rest is the quotient.
Answer:
Using the table, give the percentage associated with each unit of standard deviation in the standard normal curve to the
nearest hundredth.
х
Area, A(x) x
Area, A(x)
0.2
0.4
0.6
0.8
1.0
1.2
1.4
1.6
1.8
2.0
0.0793
0.1554
0.2257
0.2881
0.3413
0.3849
0.4192
0.4452
0.4641
0.4772
2.2
2.4
2.6
2.8
3.0
3.2
3.4
3.6
3.8
4.0
0.4861
0.4918
0.4953
0.4974
0.4987
0.4993
0.4997
0.4998
0.4999
0.5000
Standard Deviation Percentage Area
-1 to 0
81.85 %
O to +1
34.13 %
Step-by-step explanation:
Using the table, give the percentage associated with each unit of standard deviation in the standard normal curve to the
nearest hundredth.
х
Area, A(x) x
Area, A(x)
0.2
0.4
0.6
0.8
1.0
1.2
1.4
1.6
1.8
2.0
0.0793
0.1554
0.2257
0.2881
0.3413
0.3849
0.4192
0.4452
0.4641
0.4772
2.2
2.4
2.6
2.8
3.0
3.2
3.4
3.6
3.8
4.0
0.4861
0.4918
0.4953
0.4974
0.4987
0.4993
0.4997
0.4998
0.4999
0.5000
Standard Deviation Percentage Area
-1 to 0
81.85 %
O to +1
34.13 %
Using the table, give the percentage associated with each unit of standard deviation in the standard normal curve to the
nearest hundredth.
х
Area, A(x) x
Area, A(x)
0.2
0.4
0.6
0.8
1.0
1.2
1.4
1.6
1.8
2.0
0.0793
0.1554
0.2257
0.2881
0.3413
0.3849
0.4192
0.4452
0.4641
0.4772
2.2
2.4
2.6
2.8
3.0
3.2
3.4
3.6
3.8
4.0
0.4861
0.4918
0.4953
0.4974
0.4987
0.4993
0.4997
0.4998
0.4999
0.5000
Standard Deviation Percentage Area
-1 to 0
81.85 %
O to +1
34.13 %
