Your answer is going to be C
The answer to this question is B
Answer:
a) H0 : u = 28.5%
H1 : u < 28.5%
b) critical value = - 1.645
c) test statistic Z= - 1.41
d) Fail to reject H0
e) There is not enough evidence to support the professor's claim.
Step-by-step explanation:
Given:
P = 28.5% ≈ 0.285
X = 210
n = 800
Level of significance = 0.05
a) The null and alternative hypotheses are:
H0 : u = 28.5%
H1 : u < 28.5%
b) Given a 0.05 significance level.
This is a left tailed test.
The critical value =
The critical value = -1.645
c) Calculating the test statistic, we have:


Z = -1.41
d) Decision:
We fail to reject null hypothesis H0, since Z = -1.41 is not in the rejection region, <1.645
e) There is not enough evidence to support the professor's claim that the proportion of obese male teenagers decreased.
Answer:
Step-by-step explanation:
Find out the how much chlorine is in the pool .
To prove
As given
The amount of chlorine in a swimming pool varies directly with the volume of water.
The pool has 2.5 milligrams of chlorine per liter of water.
i.e
2.5 milligrams of chorine = 1 litre of water
There are 8000 gallons of water in the swimming pool.
As 1 gallons = 3.78541 litre (Approx)
Now convert 8000 gallons of water in litres.
8000 gallons = 8000 × 3.78541 litre
= 30283.28 litres
Now calculate chlorine in the pool for 30283.28 litres of waters.
As
2.5 milligrams of chlorine = 1 litre of water
2.5 × 30283.28 milligrams of chlorine = 30283.28 litre of water
75708.2 milligrams of chlorine for 30283.28 litre of water .
You use the distributive property and multiple everything inside of the parentheses by 2x^2 then everything in the parentheses by y to get 2x^4y-6x^3y^2+16x^2y^3. I think that’s the answer and I hope that helped!