Determine if the equation is linear. (1.) 2x + y=4

Twice a number, n, increased by 3 is less than the number, n, decreased by four. inequality

bonufazy [111]

Answer:

2n+3 < n-4

Step-by-step explanation:

Tooooooo easy XD

8 0

3 years ago

What is 0.472 rounded to the nearest tenth? (2 points)

MA_775_DIABLO [31]

To round 0.472 to the nearest tenth consider the hundredths' value of 0.472, which is 7 and equal or more than 5. Therefore, the tenths value of 0.472 increases by 1 to 5.

So, the answer would be 0.5.

I hope this helped!

7 0

3 years ago

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Which interval for the graphed function contams the local maximum?

Natasha2012 [34]

Answer:

$[0,2]$

Step-by-step explanation:

A local maximum or local minimum is the point where the tangent drawn to it is parallel to the x axis.

The crest of a wave is local maximum and the trough of wave is local minimum.

Here, in the graph, there are 2 troughs and 1 crest.

The crest is at $(1.55,10.8)$ . So, the local maximum is at $(1.55,10.8)$ .

The interval of the local maximum is between $x = 0$ and $x = 3$ .

So, the option that matches with the above interval is $[0,2]$ .

6 0

3 years ago

The forecast for week 13 is 747. (Enter your response rounded to the nearest whole number.) Specify the mean absolute deviatio

son4ous [18]

Answer:

a) MAD without the forecast = 43.71

MAD with the forecast = 45.59

b) MAPE = 0.097 = 9.7%

Step-by-step explanation:

642 602 656 747 663 618 731 726 679 737 664 740

Mean Absolute deviation is given as

MAD = [Σ|x - μ|]/N

We first calculate the mean

Mean = Σx/N

Mean = (642+602+656+747+663+618+731+726+679+737+664+740)/12

Mean = (8205/12) = 683.75

absolute deviations from the mean

|642-683.75| + |602-683.75| + |656-683.75| + |747-683.75| + |663-683.75| + |618-683.75| + |731-683.75| + |726-683.75| + |679-683.75| + |737-683.75| + |664-683.75| + |740-683.75|

Absolute deviations from the mean

41.75+81.75+27.75+63.25+20.75+65.75+47.25+42.25+4.75+53.25+19.75+56.25

= 524.5

MAD = [Σ|x - μ|]/N

MAD = (524.5/12)

MAD = 43.71

If we include the forecast on the 13th week

642 602 656 747 663 618 731 726 679 737 664 740 747

Mean = (8205+747)/13

Mean = 688.62

absolute deviations from the mean

|642-688.62| + |602-688.62| + |656-688.62| + |747-688.62| + |663-688.62| + |618-688.62| + |731-688.62| + |726-688.62| + |679-688.62| + |737-688.62| + |664-688.62| + |740-688.62| + |747-688.62|

Absolute deviations from the mean

= 46.62+86.62+32.62+58.38+25.62+70.62+42.38+37.38+9.62+48.38+24.62+51.38+58.38

= 592.62

MAD = (592.62/13)

MAD = 45.59.

b) MAPE is used to check forecast errors

MAPE = (1/N) Σ [|x-f|/x]

where N = Sample size = 12

x = each variable

f = the forecasted value = 747

x = 642, 602, 656, 747, 663, 618, 731, 726, 679, 737, 664, 740

Σ [|x-f|/x]

= 0.164+0.241+0.139+0+0.112+0.209+0.022+0.029+0.100+0.014+0.125+0.009

Σ [|x-f|/x] = 1.164

MAPE = (1.164/12)

MAPE = 0.097 = 9.7%

Hope this Helps!!!

7 0

3 years ago

Given that tangent squared theta = three-eighths, what is the value of secant theta?

docker41 [41]

Answer:

B) Plus-or-minus StartRoot eleven-eighths EndFraction

${ \tan }^{2} \theta = \frac{3}{8} \\ but : { \tan }^{2} \theta = { \sec }^{2} \theta - 1 \\ \therefore { \sec}^{2} \theta - 1 = \frac{3}{8} \\ { \sec }^{2} \theta = \frac{11}{8} \\ \sec( \theta) = \sqrt{ \frac{11}{8} }$

3 0

3 years ago

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Determine if the equation is linear.(1.) 2x + y=4​

Determine if the equation is linear.(1.) 2x + y=4