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Anvisha [2.4K]
3 years ago
11

What is the answer!!

Mathematics
1 answer:
Amanda [17]3 years ago
6 0

Answer:

The third choice: (x+6)(x-6)

Step-by-step explanation:

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Use the given line of best fit to approximate the rate of change relative to the scatter plot below.
shusha [124]

Answer: it’s a

Step-by-step explanation:

7 0
3 years ago
Jasmine correctly answers 70% of total questions on her math test.She correctly answers 35 questions.How many total questions we
podryga [215]
1) How many % represent a question?
70% / 35
=2%

2)How many questions that Jasmine got wrong?
30% / 2%
=15

Total questions:
15 + 35
50 questions.
6 0
3 years ago
Multiply and simplify completely:<br><br> (3x + 5) (2x2 – 3x + 2)<br> Show all work for full credit.
Bezzdna [24]

Answer:

open brackets we get

6x³ - 9x² + 6x + 10x² - 15x + 10

6x³ + x² -9x + 10

7 0
3 years ago
PLS ANSWER. The questions is attached. Dont' put like I dont' know the answer if u don't know don't answer pls.
jekas [21]

Answer:

x = 2.4

Step-by-step explanation:

see image for explanation.

Hope it helps

8 0
2 years ago
Can someone please help me
Kryger [21]

Based on definition of <em>unit</em> circle and <em>angle</em> properties on <em>Cartesian</em> plane, we find the following results: A: π/5, B: 3π/7, C: 4π/3.

<h3>How to determine angles in a unit circle</h3>

<em>Units</em> circles are commonly used to understand angles and <em>trigonometric</em> functions in a simple way. Vectors in a <em>unit</em> circle are <em>ordered</em> pairs of <em>polar</em> form: (x, y) = (cos θ, sin θ).

To solve this problem, we must take these tips into account:

  1. Angles in the <em>first</em> quadrant are within 0 < θ < π/2.
  2. Angles in the <em>second</em> quadrant are within π/2 < θ < π.
  3. Angles in the <em>third</em> quadrant are within π < θ < 3π/2.
  4. Angles in the <em>fourth</em> quadrant are within 3π/2 < θ < 2π.

Then, we have the following results: A: π/5, B: 3π/7, C: 4π/3.

To learn more on angles: brainly.com/question/13954458

#SPJ1

3 0
2 years ago
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