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In-s [12.5K]
3 years ago
5

Nadine bought 5 quarts of oil for her car. How many fluid ounces is that?

Mathematics
2 answers:
Lelu [443]3 years ago
8 0
1 quart = 32 fluid ounces.

So, 5 quarts = ? fluid ounces.

Lets solve to find ?. 

5 × 32 = 160

So, Nadine bout 160 fluid ounces (5 quarts) or oil for her car.

Hope I helped ya!! 
frozen [14]3 years ago
6 0

Answer:

5 quarts is equal to 160 fluid ounces.

Step-by-step explanation:

Nadine bought 5 quarts of oil for her car. How many fluid ounces is that?

The relation between 1 quart and number of fluid ounces is :

1 quart = 32 fluid ounces.

So, 5 quarts will be = 5\times32=160 fluid ounces.

Hence, we can say that Nadine bought 160 fluid ounces for her car.

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Answer the question about the image.
Anton [14]

Answer:

4

Step-by-step explanation:

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3 0
2 years ago
A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measure SL 42,000 ft
horsena [70]

Answer:

a= 200

b = 210

Step-by-step explanation:

My assumption is, we have to find the length of sides of rectangle

Given

perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)

area = a*b = 42,000 ft^2 (ii)

from eq (1)

2a + 2b = 820

=> 2(a+b) = 820

=> a+b = 820/2

=> a + b = 410

=> a = 410-b   (iii)

putting the value of a in eq(ii), we get

(410-b) *b = 42,000

410b - b^2 = 42,000

0 = b^2 - 410b + 42000

b^2 - 410b + 42000 = 0

b^2- 200b- 210b + 42000 = 0

b(b-200)-210(b-200) = 0

(b-200)(b-210) = 0

or

b= 210 and b = 200

if b is larger side than b =210

By putting value of b in eq(iii),

a = 410 -210 = 200

 

6 0
3 years ago
This is a 9th grade algebra question....
inna [77]
12 fluid ounces of sweat an hour 
6 0
3 years ago
The perimeter of a rectangular painting is 244 centimeters. If the width of the painting is 51 centimeters, what is the length?​
Schach [20]

Answer:

193 i think

Step-by-step explanation:

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6 0
3 years ago
For questions 1 and 2 graph the exponential function:<br> 1. y=3^x<br> 2. y=2(4.5)^x
Mumz [18]
First, we should know exponential formula, for example exp (LnA) =A, for all A>0, and as for logarythm, LnA^p=pLnA, for all A>0, and for all value of p
so y=3^x=exp[Ln(3^x)]=exp(xLn3), let's search the graph of f(x)=exp(xLn3) f is defined in R, and its teminals limits are 0, and + infinity, f' (x) = Ln3.exp(xLn3), it is positif for all value of x, the function is strictly increasing, f(0)=Ln3, please look at the figure 1
the same method with y=2(4.5)^x, we find y=exp[Ln (2(4.5)^x)]=
exp[Ln (2) +Ln(4.5)^x)], because (LnAB=LnA + LnB), so y=2.exp[Ln(4.5)^x)]=2.exp(x[Ln(4.5)]), which domain is R, nd its teminals limits are 0, and + infinity, f' (x)=2.Ln(4.5) exp(x[Ln(4.5)]), which is positif for all value of x, the function is strictly increasing,and then f(0)=2Ln(4.5)
please look the figure 2

5 0
3 years ago
Read 2 more answers
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