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Dimas [21]
3 years ago
10

Ken normally leaves work at 5:00 pm, but he is leaving 20 minutes late today. He decides to make up time by taking the toll road

instead of side streets. He can travel three times faster by taking the toll road. Create an equation in terms of x to represent the number of minutes after 5:00 pm he arrives home from work if he leaves late. Let x represent the number of minutes his normal commute takes when he leaves on time.
y = 1/3x + 20
y = 3x + 20
y = 1/3x - 20
y = 3x − 20
Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0

Answer:

The correct answer is: y=\frac{1}{3} x + 20

Step-by-step explanation:

As stated in the question that x represents the number of minutes his <em>normal</em> commute takes. Here the keyword is normal; in the <em>normal</em> commute, Ken takes side streets instead of the toll road.

However, in this scenario, we have to come up with the equation that takes Ken's commute via <em>toll road</em>.

Ken can travel 3 times faster by taking the toll road (Given), which can be represented in the mathematical terms in terms of x as follows:

x_{toll\_road}=\frac{1}{3}x

<em>Without considering Ken getting late, </em>the equation would become the following:

y=\frac{1}{3} x --- (A)

<em>As Ken is leaving late</em>, we have to incorporate that time as well by <em>adding</em> it in the aforementioned equation (A).

In this case, it's 20 minutes; therefore, the equation (A) will become:

y=\frac{1}{3} x+20

Hence, the correct answer is y=\frac{1}{3} x + 20.

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The composite shape is made up of two identical triangles and two different rectangles. What is the are of the composite shape i
AfilCa [17]

Answer: 72 u^2

<h3>Explanation:</h3>

What we know:

  • Both triangles are identical
  • Both rectangles are different
  • There are values in units^2 given
  • There are right angles

How to solve:

We need to find the area of at least one of the triangles and double it. Then, we need to find the areas of both rectangles. Finally, we need to add these areas to find the total area. The final area will be represented in units squared (u^2)

<h2>Process:</h2>

Triangles

Set up equation                                                 A = 1/2(bh)

Substitute                                                           A = 1/2(4*3)

Simplify                                                               A = 1/2(12)

Solve                                                                   A = 6

Double                                                                     *2

                                                                           A = 12 u^2

Rectangles

Set up equation                                                 A = lh

Substitute                                                           A = (14)(3)

Simplify                                                               A = 42 u^2

Set up equation                                                 A = lh

Substitute                                                           A = [14-(4+4)](3)

Simplify                                                               A = (14-8)(3)

Simplify                                                               A = (6)(3)

Multiply                                                               A = 18 u^2

Total Area

Set up equation                                                 A = R1+R2+T

Substitute                                                           A = 42 + 18 + 12

Simplify                                                               A = 60 + 12

Solve                                                                   A = 72 u^2

<h3>Answer: 72 u^2</h3>
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Answer:

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Step-by-step explanation:

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I hope I helped you! :)))

7 0
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