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wolverine [178]
2 years ago
5

He smallest network is a ______________________, which is a network of personal devices, such as the network you use when you sy

nc your cell phone and your computer.​
Computers and Technology
1 answer:
scoray [572]2 years ago
8 0
<span>The smallest network is a </span>personal area network,<span> which is a network of personal devices, such as the network you use when you sync your cell phone and your computer. </span>personal area network
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Write a program whose input is a character and a string, and whose output indicates the number of times the character appears in
Zina [86]

Answer:

Here is the C++ program:

#include <iostream> // to include input output functions

using namespace std; // to identify objects like cin cout

int counter(string userString, char character) { //function counter

   int count = 0;   // counts the no of times a character appears in the string

   for (int i=0;i<userString.length();i++)  

// loop to move through the string to find the occurrence of the character

       if (userString[i] == character) //if characters is found in the string

           count++;   //counts the occurrence of the character in the string

   return count; }   //returns the no of times character occurs in the string

int main() { //start of the main() function body

   string s; // stores the string entered by the user

   cout<<"Enter a string: "; //prompts user to enter the string

   cin>>s; //reads the string from user

   char ch; //stores the character entered by the user

   cout<<"Enter a character: "; //prompts user to enter a character

   cin>>ch; //reads the character from user

   cout << counter(s, ch) << endl; }  

//calls counter function to find the number of times a character occurs in the //string

Explanation:

The counter function works as following:

It has a count variable which stores the number of occurrences of a character in the userString.

It uses a for loop which loops through the entire string.

It has i position variable which starts with the first character of the string and checks if the first character of userString matches with the required character.

If it matches the character then count variable counts the first occurrence of the character and in the userString and is incremented to 1.

If the character does not match with the first character of the userString then the loops keeps traversing through the userString until the end of the userString is reached which is specified by the length() function which returns the length of the string.

After the loop ends the return count statement is used to return the number of occurrences of the character in the userString.

The main() function prompts the user to enter a string and a character. It then calls counter() function passing string s and character ch arguments to it in order to get the number of times ch appears in s.

The output is attached in a screenshot.

6 0
3 years ago
Write code for a function with the following prototype: /* Addition that saturates to TMin or TMax */ int saturating_add(int x,
Kazeer [188]

Answer:

See explaination

Explanation:

program code.

/* PRE PROCESSOR DIRECTIVES */

#include<stdio.h>

/* PRE-DEFINED VALUES FOR TMAX AND TMIN */

#define TMax 2147483647

#define TMin (-TMax -1)

/* saturating_add(int,int) METHOD IS CALLED HERE */

int saturating_add(int firstNumber, int secondNumber)

{

/*

FOR BETTER UNDERSTANDING, LETS TAKE TEST CASE,

WHERE firstNumber = 5 AND secondNumber = 10

*/

int w = sizeof(firstNumber) << 3;

/*

sizeof(firstNumber) VALUE IS 4, SO USING BINARY LEFT SHIFT OPERATOR TO THREE PLACES,

WE HAVE NOW VALUE 32, ASSIGNED TO w

*/

/* ADDITION IS CALCULATED => 15 */

int addition = firstNumber + secondNumber;

/*

MASK INTEGER VARIABLE IS TAKEN

mask BIT IS LEFT SHIFTED TO 31 PLACES => 2^31 IS THE NEW VALUE

*/

int mask = 1 << (w - 1);

/* FIRST NUMBER MOST SIGNIFICANT BIT IS CALCULATED BY USING AND OPERATOR */

int msbFirstNumber = firstNumber & mask;

/* SECOND NUMBER MOST SIGNIFICANT BIT IS CALCULATED BY USING AND OPERATOR */

int msbSecondNumber = secondNumber & mask;

/* MOST SIGNIFICANT BIT OF ADDITION IS CALCULATED BY USING AND OPERATOR */

int msbAddition = addition & mask;

/* POSITIVE OVERFLOW IS DETERMINED */

int positiveOverflow = ~msbFirstNumber & ~msbSecondNumber & msbAddition;

/* NEGATIVE OVERFLOW IS DETERMINED */

int negativeOverflow = msbFirstNumber & msbSecondNumber & !msbAddition;

/* THE CORRESPONDING VALUE IS RETURNED AS PER THE SATURATING ADDITION RULES */

(positiveOverflow) && (addition = TMax);

(negativeOverflow) && (addition = TMin);

return addition;

}

/* MAIN FUNCTION STARTS HERE */

int main(){

/* TEST CASE */

int sum = saturating_add(5, 10);

/* DISPLAY THE RESULT OF TEST CASE */

printf("The Sum Is : %d\n\n",sum);

}

7 0
3 years ago
Your company has purchased another company that also uses Windows Server 2016 and Active Directory. Both companies need to be ab
Scorpion4ik [409]

Answer:

Create a two-way forest trust

Explanation:

The aim here is to ensure that both companies are able to access the forest resources of each other. The creation of a Two-way Forest Trust would guarantee that as if the Two-way Forest Trust is created between Forest A and Forest B, being the forest resources of the two companies respectively, then all the domains in Forest A will trust every domain in Forest B and vice versa.

5 0
3 years ago
Think of a recent occasion when you became upset with a friend or family member. How did you handle the situation? How did you c
bekas [8.4K]

Answer:

You would identify the problem together with the person or persons involved.

Explanation:

4 0
2 years ago
a 0.600 kg dynamics trolley has 1.5 kg load added. It is launched with a force of 10.n what is the acceleration
Anastaziya [24]

Answer:

acceleration = 4.76 m/s²

Explanation:

Given that"

the mass of the dynamic trolley = 0.6 kg

the mass of the load  = 1.5 kg

total mass = (0.6 + 1.5) kg = 2.1 kg

the force = 10 N

Thus;

using the formula of force which is;

Force = mass × acceleration

10 = 2.1  × acceleration

acceleration = 10/2.1

acceleration = 4.76 m/s²

7 0
2 years ago
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