Kill la Kill
Evangaleon
Blue Exorcist
The Devil is a Part Timer
Berserk
Death Note
K
A Boring World Where The Concept of Jokes Does not Exist
Psycho Pass
Elfen Lied
Soul Eater
Fairy Tale
Naruto
Using the knowledge in computational language in LC-3 Assembly it is possible to write a code that replaces the value in R0 with its absolute value
<h3>Writting the code </h3>
.ORIG x0200
START
AND R0, R0, #0 ; copy R0 to itself to set the condition codes based on R0;
; i.e performing addition operation with Zero option to set the flags
BRzp DONE ; if R0 is NON-NEGATIVE, skip the negation (already correct);
; Branch to DONE if number is poistive
NOT R0, R0 ; R0 is negative, so negate it i.e taking 2's complement
ADD R0, R0, #1 ; R0 = -R0 is performed successfully
DONE BR START
.END
See more about LC-3 Assembly at brainly.com/question/12978370
#SPJ1
D. A window the rest are incorrect
Answer:
b. lw $t4, 4($t0)
c. add $t3, $t5, $t4
Explanation:
Pipeline hazard prevents other instruction from execution while one instruction is already in process. There is pipeline bubbles through which there is break in the structural hazard which preclude data. It helps to stop fetching any new instruction during clock cycle.