Answer:
E(w) = 1600000
v(w) = 240000
Step-by-step explanation:
given data
sequence = 1 million iid (+1 and +2)
probability of transmitting a +1 = 0.4
solution
sequence will be here as
P{Xi = k } = 0.4 for k = +1
0.6 for k = +2
and define is
x1 + x2 + ................ + X1000000
so for expected value for W
E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1
as per the linear probability of expectation
E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)
E(w) = 1600000
and
for variance of W
v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2
v(w) = V x1 + V x2 + ................ + V X1000000
here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j
so
v(w) = 1000000 ( v(x) )
v(w) = 1000000 ( 0.24)
v(w) = 240000
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
First you subtract 242 from 1250 which gives you 1080. Then you divide it by 8 which gives you 126. Multiply this value by 3 and this shows that Haryati received $378. Hope this is helpful.
we know that, the mixture amount is the sum of 11 + p, or
11 + p = m.
we also know that, the total value is also a sum of
25.3 + 4.5p = 3.29m.
Answer:
5
Step-by-step explanation:
We can express 125 as 5 x 5 x 5. Therefore, the value of the cube root of 125 is 5.
![\sqrt[3]{125} = \sqrt[3]{5 \times 5 \times 5} = 5](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B125%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B5%20%5Ctimes%205%20%5Ctimes%205%7D%20%20%3D%205)
