Answer:
0.6763154335
Step-by-step explanation:
because. 10%is the same as 10 over 100 .because percent means 100. so you say 100÷10=10. then you say 10×14.786. this is how I got the answer.
Answer:
See explanation
Step-by-step explanation:
1 step:
n=1, then
![\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2](https://tex.z-dn.net/?f=%5Csum%20%5Climits_%7Bj%3D1%7D%5E1%202%5Ej%3D2%5E1%3D2%5C%5C%20%5C%5C2%282%5E1-1%29%3D2%282-1%29%3D2%5Ccdot%201%3D2)
So, for j=1 this statement is true
2 step:
Assume that for n=k the following statement is true
![\sum \limits_{j=1}^k2^j=2(2^k-1)](https://tex.z-dn.net/?f=%5Csum%20%5Climits_%7Bj%3D1%7D%5Ek2%5Ej%3D2%282%5Ek-1%29)
3 step:
Check for n=k+1 whether the statement
![\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)](https://tex.z-dn.net/?f=%5Csum%20%5Climits_%7Bj%3D1%7D%5E%7Bk%2B1%7D2%5Ej%3D2%282%5E%7Bk%2B1%7D-1%29)
is true.
Start with the left side:
![\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)](https://tex.z-dn.net/?f=%5Csum%20%5Climits%20_%7Bj%3D1%7D%5E%7Bk%2B1%7D2%5Ej%3D%5Csum%20%5Climits%20_%7Bj%3D1%7D%5Ek2%5Ej%2B2%5E%7Bk%2B1%7D%5C%20%5C%20%28%5Cast%29)
According to the 2nd step,
![\sum \limits_{j=1}^k2^j=2(2^k-1)](https://tex.z-dn.net/?f=%5Csum%20%5Climits_%7Bj%3D1%7D%5Ek2%5Ej%3D2%282%5Ek-1%29)
Substitute it into the ![\ast](https://tex.z-dn.net/?f=%5Cast)
![\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)](https://tex.z-dn.net/?f=%5Csum%20%5Climits%20_%7Bj%3D1%7D%5E%7Bk%2B1%7D2%5Ej%3D%5Csum%20%5Climits%20_%7Bj%3D1%7D%5Ek2%5Ej%2B2%5E%7Bk%2B1%7D%3D2%282%5Ek-1%29%2B2%5E%7Bk%2B1%7D%3D2%5E%7Bk%2B1%7D-2%2B2%5E%7Bk%2B1%7D%3D2%5Ccdot%202%5E%7Bk%2B1%7D-2%3D2%5E%7Bk%2B2%7D-2%3D2%282%5E%7Bk%2B1%7D-1%29)
So, you have proved the initial statement
The square of a prime number is not prime.
a) let x ∈ R, If x ∈ {prime numbers}, then
∉{prime numbers}
there says that if x is a real and x is in the set of the prime numbers, then the square of x isn't in the set of prime numbers.
b) Prove or disprove the statement.
ok, if x is a prime number, then x only can be divided by himself. Now is easy to see that
= x*x can be divided by himself and x, then x*x is not a prime number, because can be divided by another number different than himself
(-8,-5). If you think about it, for a rectangle, the x-coordinates must be the same in two pairs and the y-coordinates must be the same in two pairs. Since there are already 2 0's, 2 1's, you need a -8 and -5 to complete it. Hence, the last coordinate is (-8,-5)
Answer:
![2.6\times 10^{19}m^{3}](https://tex.z-dn.net/?f=2.6%5Ctimes%2010%5E%7B19%7Dm%5E%7B3%7D)
Step-by-step explanation:
we have given thickness of atmosphere =50 km
radius of earth =6400 km
average temperature of atmosphere=15°C
Average pressure of atmosphere= 0.20 atm
we have to calculate the volume of atmosphere
so the we have to calculate the volume of atmosphere = ( volume of earth +atmosphere) - volume of earth
volume of atmosphere =![\frac{4}{3}\times\pi \times \left ( 6400+50 \right )^{3}-\frac{4}{3}\times \pi\times 6400^3](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Ctimes%5Cpi%20%5Ctimes%20%5Cleft%20%28%206400%2B50%20%5Cright%20%29%5E%7B3%7D-%5Cfrac%7B4%7D%7B3%7D%5Ctimes%20%5Cpi%5Ctimes%206400%5E3)
=![2.6\times 10^{19}m^{3}](https://tex.z-dn.net/?f=2.6%5Ctimes%2010%5E%7B19%7Dm%5E%7B3%7D)