N^2 + n - 120 = 0
Quadratic formula
a = 1, b = 1, c = -120
n = [-1 plus or minus root(1^2 - 4(1)(-120))] / 2(1)
n = (-1 plus or minus root481)/2
n =(approximately) 10.5 or -11.5
Answer:
g(f): x -> 2(x-7)=2x-14 , g(f)(-1)=2*(-1)-14=-16
Step-by-step explanation:
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