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Alecsey [184]
3 years ago
11

Solve: x + y = 73x - 2y = 11By using Substituting method.​

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
8 0

\large\underline{\sf{Solution-}}

\sf  \longmapsto x + y = 7 \: \: - - - (i)

\sf  \longmapsto 3x - 2y = 11 \: \: - - - (ii)

<u>By first equation,</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x = 7 - y

<u>Now, we can find the original value of y.</u>

\sf \longmapsto 3x - 2y = 11

\sf  \longmapsto 3(7 - y) - 2y = 11

\sf  \longmapsto 21 - 3y - 2y = 11

\sf  \longmapsto 21 - 5y = 11

\sf  \longmapsto - 5y = 11 - 21

\sf  \longmapsto - 5y =  - 10

\sf  \longmapsto y = \dfrac{ - 10}{ - 5}

\sf  \longmapsto y = 2

<u>Now, we can find the original value of x.</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x + 2 = 7

\sf  \longmapsto x = 7 - 2

\sf  \longmapsto x = 5

Therefore, the values of x and y are 5 and 2 respectively.

Ierofanga [76]3 years ago
8 0

Step-by-step explanation:

x+y=7 _____eqn(1)

3x-2y=11____ eqn(2)

Now, Multiply eqn 1 by 3

3(x+y=7)

<u>3</u><u>x</u><u>+</u><u>3</u><u>y</u><u>=</u><u>2</u><u>1</u><u> </u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u> </u><u>eqn(</u><u>3</u><u>)</u>

Adding eq 3 to eqn 2

3x+3y=21

3x-2y=11

________

0 5y=10

y= 10/5

<u> </u><u> </u><u> </u><u>y=</u><u>2</u>

put the value of y in eqn 1

x+y=7

x+2=7

x=7-2

<u>x=</u><u>5</u>

┐( ̄ヘ ̄)┌ <u>Hope</u><u> </u><u>this</u><u> is</u><u> </u><u>ryt </u><u>ans!</u><u>!</u><u>!</u>

<u>\:  \:  \:  \:  \:</u>

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