Question

Solve: x + y = 73x - 2y = 11By using Substituting method.​

Answer 1

$\large\underline{\sf{Solution-}}$

$\sf \longmapsto x + y = 7 \: \: - - - (i)$

$\sf \longmapsto 3x - 2y = 11 \: \: - - - (ii)$

By first equation,

$\sf \longmapsto x + y = 7$

$\sf \longmapsto x = 7 - y$

Now, we can find the original value of y.

$\sf \longmapsto 3x - 2y = 11$

$\sf \longmapsto 3(7 - y) - 2y = 11$

$\sf \longmapsto 21 - 3y - 2y = 11$

$\sf \longmapsto 21 - 5y = 11$

$\sf \longmapsto - 5y = 11 - 21$

$\sf \longmapsto - 5y = - 10$

$\sf \longmapsto y = \dfrac{ - 10}{ - 5}$

$\sf \longmapsto y = 2$

Now, we can find the original value of x.

$\sf \longmapsto x + y = 7$

$\sf \longmapsto x + 2 = 7$

$\sf \longmapsto x = 7 - 2$

$\sf \longmapsto x = 5$

Therefore, the values of x and y are 5 and 2 respectively.

Answer 2

Step-by-step explanation:

x+y=7 _____eqn(1)

3x-2y=11____ eqn(2)

Now, Multiply eqn 1 by 3

3(x+y=7)

3x+3y=21 _____ eqn(3)

Adding eq 3 to eqn 2

3x+3y=21

3x-2y=11

________

0 5y=10

y= 10/5

y=2

put the value of y in eqn 1

x+y=7

x+2=7

x=7-2

x=5

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