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barxatty [35]
4 years ago
10

1. The following formula relates the quantities temperature in Celsius (C) and temperature in kelvins (K).

Mathematics
2 answers:
aev [14]4 years ago
5 0
A) T(K)<span> = </span>T(°C)<span> + 273.15
or
</span>T (°C) <span>= </span>T(K)<span> - 273.15
</span>
b) T(K) = 23 + 273.15
    T(K) = 296.15 Kelvin

c) T (°C) = T(K) - 273.15
    T (°C) = 300 - 273.15
    T (°C) = 26.85 °C
So,
300 kelvins > 25 degrees Celsius
Ad libitum [116K]4 years ago
4 0
(b) If the temperature is 23 in degrees Celsius, what is the temperature in kelvins? Show your work.

C = K − 273.15
23 = K - 273.15
296.15 Kelvin

(c) Which is greater, 300 kelvins or 25 degrees Celsius? Show your work.

To compare, we need to convert both to the same units. We do as follows:

300 Kelvin
25+273.15 = 298.15 K

Therefore, 300 Kelvin is larger.
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If m&lt;2 =3x + 14 and m&lt;7 =5x -60 then find the measure of angle 3
r-ruslan [8.4K]

Answer:

∠ 3 = 55°

Step-by-step explanation:

∠ 2 and ∠ 7 are corresponding angles and are congruent, then

5x - 60 = 3x + 14 ( subtract 3x from both sides )

2x - 60 = 14 ( add 60 to both sides )

2x = 74 ( divide both sides by 2 )

x = 37

∠ 2 = 3x + 14 = 3(37) + 14 = 111 + 14 = 125°

∠ 2 and ∠ 3 are adjacent angles on a straight line and sum to 180° , so

125° + ∠ 3 = 180° ( subtract 125° from both sides )

∠ 3 = 55°

7 0
3 years ago
The polygons are similar. Find x and y. The images are not drawn to scale.
Alja [10]
The correct answer to this question is letter "D. x = 21, y = 14."
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27 : x - 3
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18 / 12 = 27 / x - 3
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54 = 3x - 9
3x = 54 + 9
3x = 63
x = 21

18 / 12 = 24 / y + 2
3  / 2 = 24 / y + 2
48 = 3y + 6
3y = 48 - 6
3y = 42
y = 14


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