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Kaylis [27]
3 years ago
10

Please can someone help me answer these questions? Would be really grateful if it was done by the 12th of January. Thank you :)

xo

Mathematics
2 answers:
NikAS [45]3 years ago
7 0
1) 4g+5=37 => 4g=32 => g=8 
2)c/6=5 => x=6*5=> x=30
3)(f+4)/5=3 => f+4=15 => f=11
4)5(b+6)=30 => b+6=6 => b=0
5)5(a-5)=60 => a-5=12 => a=17
6)5(e+2)=45 => e+2=9 =>e=7
7)3(d-5)=12 => d-5=4=> d=9
8)4(m-4)=16 => m-4=4 => m=8
9)5(q+6)=30 => q+6=6 =>q=0
10) h/3+7=6 => h/3=1 => h=3
11)3c+5=3 => 3c=-2 => c= -2/3
12)x/3+7=6 => x/3= -1 => x=-3
13)6p-1=2 => 6p=3 => p=3/6=1/2
14)3(2d-7)=27 => 2d-7=9 => 2d=16 => d=8
15)2(b-3)=5 => b-3=2,5 => b=5,5
16)3(y-1)=1 => y-1=1/3 => y=4/3
17)5v+3=9 => 5v=6 => v= 6/5
18)(n-3)/6=3 => n-3=18 => n=21
19)(t+10)/4=1 => t+10=4 => t= -6
20)(3c+4)/3=5 => 3c+4=15 => 3c=11 => c=11/3
Hope that helps.
Good luck!! ^^
FrozenT [24]3 years ago
6 0
1. 4g= 37-5
 ⇒ 4g= 32
⇒ g= 32/4
⇒ g= 8

2. c= 5*6
⇒ c= 30

3. f+4= 3*5
⇒f+4= 15
⇒ f= 15-4
⇒ f= 11.

4. b+6= 30/5
⇒ b+6= 6
⇒ b= 6-6
⇒ b=0

5. a-5= 60/5
⇒ a-5= 12
⇒ a= 12+5
⇒ a= 17

6. e+2= 45/5
⇒ e+2= 9
⇒ e= 9-2
⇒ e= 7

7. d-5= 12/3
⇒ d-5= 4
⇒ d= 4+5
⇒ d= 9

8. m-4= 16/4
⇒ m-4= 4
⇒ m= 4+4
⇒ m= 8

9. q+6= 30/5
⇒ q+6= 6
⇒ q= 6-6
⇒ q= 0

10. h/3= 3+5
⇒ h/3= 8
⇒ h= 8*3
⇒ h= 24

11. 3c= 3-5
⇒ 3c= -2
⇒ c= -2/3

12. x/3= 6-7
⇒ x/3= -1
⇒ x= -1*3
⇒ x= -3

13. 6p= 2+1
⇒ 6p= 3
⇒ p= 3/6
⇒ p= 1/2

14. 2d-7= 27/3
⇒ 2d-7= 9
⇒ 2d= 9+7
⇒ 2d= 16
⇒ d= 16/2
⇒ d=8

15. b-3= 5/2
⇒ b-3= 2.5
⇒ b= 2.5+3
⇒ b= 5.5

16. y-1= 1/3
⇒ y= 1/3+1
⇒ y= 1 1/3

17. 5v= 9-3
⇒ 5v= 6
⇒ v= 6/5
⇒ v= 1.2

18. n-3 = 3*6
⇒ n-3= 18
⇒ n= 18+3
⇒ n= 21

19. t+10= 1*4
⇒ t+10= 4
⇒ t= 4-10
⇒ t= -6

20. 3c+4= 3*5
⇒ 3c+4= 15
⇒ 3c= 15-4
⇒ 3c= 11
⇒ c= 11/3
⇒ c= 3 2/3

Hope this helps~
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Step-by-step explanation:

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Since Michael has decided to dedicate the entirety of his signing bonus towards paying his debt, then that is a constant and one-off payment.

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7 0
3 years ago
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2 years ago
Paul has 12 coins in his pocket, consisting entirely of dimes and quarters. If he has a total of 195 cents in coins, how many co
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Let x be the number of dimes

and y be the number of quarters

Total number of coins = 12

So number of dimes + number of quarters = total number of coins

x + y = 12 ---------> equation 1

We know, 1 Quarter = 25 cents, 1 Dime = 10 cents, total cents = 196

y quarters = 25y cents , x dimes = 10x cents

x dimes + y quarters = 195 cents

10x + 25y = 195 -----------> equation 2

Now solve both equations

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y = 12-x

Now substitute y in second equation

10x + 25(12-x) = 195

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The number of dimes = 7

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8 0
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