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Given information
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First showing : 1.30pm
Second showing : 4.15 pm
Inbetween : 1/2 hour break
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Find the time the first showing ends
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1/2 hours before 4.15pm
⇒ 30 mins before 4.15pm
⇒ 3.45pm
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Calculate the duration of the firs show
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1.30pm to 3.30pm = 2 hours
3.30pm to 3.45pm = 15 mins
Total duration = 2 hours 15 mins
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Answer: 2 hours 15 mins
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Answer:
see explanation
Step-by-step explanation:
This is an example of the Altitude - on - Hypotenuse theorem.
The altitude that is perpendicular to the hypotenuse of a right triangle.
The two triangles formed are similar to the given triangle and to each other.
x² = (smaller part) × (larger part) of main hypotenuse
x² = 6 + 19 = 114 ( square root both sides )
x ≈ 10.68 ( nearest hundredth )
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y² = ( smaller part) × (whole part) of main hypotenuse
y² = 6 × 25 = 150 ( square root both sides )
y ≈ 12.25 ( nearest hundredth )
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z² = ( larger part) × (whole part) of main diagonal
z² = 19 × 25 = 475 ( square root both sides )
z ≈ 21.79 ( nearest hundredth )
Answer:
$10 = 5 $5 = 11 $1 = 122
Step-by-step explanation:
i take the same class
Horizontal Shrink: y = cos 2x or if the coefficient of x is greater than 1
Vertical Stretch: y = 2 cos x or if the coefficient if cos x is greater than 1
Horizontal Stretch: y = cos (1/2) x or if the coefficient of x is less than 1
Vertical Shrink: y = (1/2) cos x or the coefficient of cos x is less than 1
The base value is 1 since it is the original coefficient of x and cos x. The values would adjust depending on the original coefficients.